Get img src with PHP

Question

I would like to get the SRC attribute into a variable in this example    lt img border  0  src   images image jpg  alt  Image  width  100  height  100    gt    So for example - I would like to get a variable  foo     images image jpg   Important  The src attribute will be dynamic  so it mustn t be hardcoded  Is there any quick and easy way to do this   Thanks   EDIT  The image will be a part of a huge string that is basically the content of a news story  So the image is just a part of that   EDIT2  There will be more images in this string  and I would only want to get the src of the first one  Is this possible

User · Answer

imgTag    lt  lt  lt  LOB  lt img border  quot 0 quot  src  quot  images image jpg quot  alt  quot Image quot  width  quot 100 quot  height  quot 100 quot    gt   lt img border  quot 0 quot  src  quot  images not match image jpg quot  alt  quot Image quot  width  quot 100 quot  height  quot 100 quot    gt  LOB   preg match    lt img   src   quot           quot         gt  i    imgTag   matches    imgSrc    matches 1     DEMO   NOTE  You should use an HTML Parser like DOMDocument and NOT a regex

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You would be better off using a DOM parser for this kind of HTML parsing  Consider this code    html     lt img id  12  border  0  src   images image jpg           alt  Image  width  100  height  100    gt     doc   new DOMDocument    libxml use internal errors true    doc- gt loadHTML  html      loads your html  xpath   new DOMXPath  doc    nodelist    xpath- gt query    img       find your image  node    nodelist- gt item 0      gets the 1st image  value    node- gt attributes- gt getNamedItem  src  - gt nodeValue  echo  src  value n      prints src of image   OUTPUT   src  images image jpg

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Use a HTML parser like DOMDocument and then evaluate the value you re looking for with DOMXpath    html     lt img id  12  border  0  src   images image jpg           alt  Image  width  100  height  100    gt      doc   new DOMDocument     doc- gt loadHTML  html    xpath   new DOMXPath  doc    src    xpath- gt evaluate  string   img  src         images image jpg    Or for those who really need to save space    xpath   new DOMXPath  DOMDocument  loadHTML  html     src    xpath- gt evaluate  string   img  src       And for the one-liners out there    src    string  reset simplexml import dom DOMDocument  loadHTML  html  - gt xpath    img  src

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str     lt img border  0  src    images image jpg   alt  Image  width  100  height  100   gt     preg match    src                      str   match      find src  X  or src  X   split   preg split             match 0       split by quotes   src    split 1      X between quotes  echo  src    Other regexp s can be used to determine if the pulled src tag is a picture like so   if preg match     jpg  3      gif  3      jpeg  3      bmp  3      png  3        src     1      its an image

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I know people say you shouldn t use regular expressions to parse HTML  but in this case I find it perfectly fine    string     lt img border  0  src   images image jpg  alt  Image  width  100  height  100    gt    preg match    lt img    src                U    string   result    foo   array pop  result

User · Answer

There could be two easy solutions    HTML it self is an xml so you can use any XML parsing method if u load the tag as XML and get its attribute tottally dynamically even dom data attribute  like data-time or anything       Use any html parser for php  like  http   mbe ro 2009 06 21 php-html-to-array-working-one  or  php parse html to array Google this

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I have done that the more simple way  not as clean as it should be but it was a quick hack   htmlContent   file get contents  pageURL        read all image tags into an array preg match all    lt img   gt    gt  i   htmlContent   imgTags     for   i   0   i  lt  count  imgTags 0     i           get the source string   preg match   src          i   imgTags 0   i    imgage         remove opening  src   tag  can t get the regex right    origImageSrc     str ireplace   src           imgage 0         will output all your img src s within the html string print r  origImageSrc

[php] Get img src with PHP

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