How to extract text from a string using sed

Question

My example string is as follows   This is 02G05 a test string 20-Jul-2012   Now from the above string I want to extract 02G05  For that I tried the following regex with sed    echo  This is 02G05 a test string 20-Jul-2012    sed -n    d G d  p    But the above command prints nothing and the reason I believe is it is not able to match anything against the pattern I supplied to sed   So  my question is what am I doing wrong here and how to correct it   When I try the above string and pattern with python I get my result   gt  gt  gt  re findall r  d G d   st    02G05    gt  gt  gt

User · Answer

Try this instead   echo  This is 02G05 a test string 20-Jul-2012    sed  s       0-9   G 0-9          1     But note  if there is two pattern on one line  it will prints the 2nd

User · Answer

The pattern  d might not be supported by your sed  Try  0-9  or    digit    instead   To only print the actual match  not the entire matching line   use a substitution   sed -n  s      0-9  0-9  G 0-9  0-9        1 p

User · Answer

How about using grep -E   echo  This is 02G05 a test string 20-Jul-2012    grep -Eo   0-9  G 0-9

User · Answer

sed doesn t recognize  d  use    digit    instead  You will also need to escape the   or use the -r switch  -E on OS X    Note that  0-9  works as well for Arabic-Hindu numerals

User · Answer

Try using rextract  It will let you extract text using a regular expression and reformat it   Example     echo  This is 02G05 a test string 20-Jul-2012      rextract     d  G  d        1    2G05

[regex] How to extract text from a string using sed?

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