How do I fetch lines before after the grep result in bash

Question

I want a way to search in a given text  For that  I use grep  grep -i  quot my regex quot   That works  But given the data like this  This is the test data This is the error data as follows                                               Error data ends  Once I found the word error  using grep -i error data   I wish to find the 10 lines that follow the word error  So my output should be                                                Error data ends  Are there any way to do it

User · Accepted Answer

You can use the -B and -A to print lines before and after the match   grep -i -B 10  error  data   Will print the 10 lines before the match  including the matching line itself

User · Answer

This prints 10 lines of trailing context after matching lines  grep -i  my regex  -A 10   If you need to print 10 lines of leading context before matching lines   grep -i  my regex  -B 10   And if you need to print 10 lines of leading and trailing output context   grep -i  my regex  -C 10   Example  user box    cat out  line 1 line 2 line 3 line 4 line 5 my regex line 6 line 7 line 8 line 9 user box      Normal grep  user box    grep my regex out  line 5 my regex user box       Grep exact matching lines and 2 lines after  user box    grep -A 2 my regex out    line 5 my regex line 6 line 7 user box       Grep exact matching lines and 2 lines before  user box    grep -B 2 my regex out   line 3 line 4 line 5 my regex user box       Grep exact matching lines and 2 lines before and after  user box    grep -C 2 my regex out   line 3 line 4 line 5 my regex line 6 line 7 user box       Reference  manpage grep  -A num --after-context num      Print num lines of trailing context after matching lines  -B num --before-context num      Print num lines of leading context before matching lines  -C num -num --context num      Print num lines of leading and trailing output context

User · Answer

The way to do this is near the top of the man page  grep -i -A 10  error data

User · Answer

Try this   grep -i -A 10  my regex    -A 10 means  print ten lines after match to  my regex

[bash] How do I fetch lines before/after the grep result in bash?

Examples related to bash

Examples related to shell

Examples related to ubuntu