I see people are using any
to gather another list to see if an item exists in a list, but is there a quick way to just do?:
if list.contains(myItem):
# do something
This question is related to
python
list
search
collections
contains
The list method index
will return -1
if the item is not present, and will return the index of the item in the list if it is present. Alternatively in an if
statement you can do the following:
if myItem in list:
#do things
You can also check if an element is not in a list with the following if statement:
if myItem not in list:
#do things
I came up with this one liner recently for getting True
if a list contains any number of occurrences of an item, or False
if it contains no occurrences or nothing at all. Using next(...)
gives this a default return value (False
) and means it should run significantly faster than running the whole list comprehension.
list_does_contain = next((True for item in list_to_test if item == test_item), False)
In addition to what other have said, you may also be interested to know that what in
does is to call the list.__contains__
method, that you can define on any class you write and can get extremely handy to use python at his full extent.
A dumb use may be:
>>> class ContainsEverything:
def __init__(self):
return None
def __contains__(self, *elem, **k):
return True
>>> a = ContainsEverything()
>>> 3 in a
True
>>> a in a
True
>>> False in a
True
>>> False not in a
False
>>>
Source: Stackoverflow.com