I think that you should use the new PHP DateTime object as it has no issues doing dates beyond the 32 bit restrictions that strtotime() has. Here's an example of how you would get today's date at midnight.
$today = new DateTime();
$today->setTime(0,0);
Or if you're using PHP 5.4 or later you can do it this way:
$today = (new DateTime())->setTime(0,0);
Then you can use the echo $today->format('Y-m-d'); to get the format you want your object output as.
function getTodaysTimeStamp() {_x000D_
const currentTimeStamp = Math.round(Date.now() / 1000);_x000D_
const startOfDay = currentTimeStamp - (currentTimeStamp % 86400);_x000D_
return { startOfDay, endOfDay: startOfDay + 86400 - 1 };_x000D_
}_x000D_
_x000D_
// starts from sunday_x000D_
function getThisWeeksTimeStamp() {_x000D_
const currentTimeStamp = Math.round(Date.now() / 1000);_x000D_
const currentDay = new Date(currentTimeStamp * 1000);_x000D_
const startOfWeek = currentTimeStamp - (currentDay.getDay() * 86400) - (currentTimeStamp % 86400);_x000D_
return { startOfWeek, endOfWeek: startOfWeek + 7 * 86400 - 1 };_x000D_
}_x000D_
_x000D_
_x000D_
function getThisMonthsTimeStamp() {_x000D_
const currentTimeStamp = Math.round(Date.now() / 1000);_x000D_
const currentDay = new Date(currentTimeStamp * 1000);_x000D_
const startOfMonth = currentTimeStamp - ((currentDay.getDate() - 1) * 86400) - (currentTimeStamp % 86400);_x000D_
const currentMonth = currentDay.getMonth() + 1;_x000D_
let daysInMonth = 0;_x000D_
if (currentMonth === 2) daysInMonth = 28;_x000D_
else if ([1, 3, 5, 7, 8, 10, 12].includes(currentMonth)) daysInMonth = 31;_x000D_
else daysInMonth = 30;_x000D_
return { startOfMonth, endOfMonth: startOfMonth + daysInMonth * 86400 - 1 };_x000D_
}_x000D_
_x000D_
_x000D_
console.log(getTodaysTimeStamp());_x000D_
console.log(getThisWeeksTimeStamp());_x000D_
console.log(getThisMonthsTimeStamp());In more object way:
$today = new \DateTimeImmutable('today');
example:
echo (new \DateTimeImmutable('today'))->format('Y-m-d H:i:s');
// will output: 2019-05-16 00:00:00
and:
echo (new \DateTimeImmutable())->format('Y-m-d H:i:s');
echo (new \DateTimeImmutable('now'))->format('Y-m-d H:i:s');
// will output: 2019-05-16 14:00:35
If you are using Carbon you can do the following. You could also format this date to set an Expire HTTP Header.
Carbon::parse('tomorrow midnight')->format(Carbon::RFC7231_FORMAT)
You are looking to calculate the time of the most recent celestial event where the sun has passed directly below your feet, adjusted for local conventions of marking high noon and also potentially adjusting so that people have enough daylight left after returning home from work, and for other political considerations.
Daunting right? Actually this is a common problem but the complete answer is location-dependent:
$zone = new \DateTimeZone('America/New_York'); // Or your own definition of “here”
$todayStart = new \DateTime('today midnight', $zone);
$timestamp = $todayStart->getTimestamp();
Potential definitions of “here” are listed at https://secure.php.net/manual/en/timezones.php
Updated Answer in 19 April, 2020
Simply we can do this:
$today = date('Y-m-d 00:00:00');
$today_at_midnight = strtotime(date("Ymd"));
should give you what you're after.
explanation
What I did was use PHP's date function to get today's date without any references to time, and then pass it to the 'string to time' function which converts a date and time to a epoch timestamp. If it doesn't get a time, it assumes the first second of that day.
References: Date Function: http://php.net/manual/en/function.date.php
String To Time: http://us2.php.net/manual/en/function.strtotime.php
Today at midnight. Easy.
$stamp = mktime(0, 0, 0);
$timestamp = strtotime('today midnight');
is the same as
$timestamp = strtotime('today');
and it's a little less work on your server.
$midnight = strtotime('midnight'); is valid
You can also try out
strtotime('12am') or strtotime('[input any time you wish to here. e.g noon, 6pm, 3pm, 8pm, etc]'). I skipped adding today before midnight because the default is today.
Source: Stackoverflow.com