[c#] How to concatenate two IEnumerable<T> into a new IEnumerable<T>?

I have two instances of IEnumerable<T> (with the same T). I want a new instance of IEnumerable<T> which is the concatenation of both.

Is there a build-in method in .Net to do that or do I have to write it myself?

You can use below code for your solution:-

public void Linq94() 
{ 
    int[] numbersA = { 0, 2, 4, 5, 6, 8, 9 }; 
    int[] numbersB = { 1, 3, 5, 7, 8 }; 

    var allNumbers = numbersA.Concat(numbersB); 

    Console.WriteLine("All numbers from both arrays:"); 
    foreach (var n in allNumbers) 
    { 
        Console.WriteLine(n); 
    } 
}

// The answer that I was looking for when searching
public void Answer()
{
    IEnumerable<YourClass> first = this.GetFirstIEnumerableList();
    // Assign to empty list so we can use later
    IEnumerable<YourClass> second = new List<YourClass>();

    if (IwantToUseSecondList)
    {
        second = this.GetSecondIEnumerableList();  
    }
    IEnumerable<SchemapassgruppData> concatedList = first.Concat(second);
}

The Concat method will return an object which implements IEnumerable<T> by returning an object (call it Cat) whose enumerator will attempt to use the two passed-in enumerable items (call them A and B) in sequence. If the passed-in enumerables represent sequences which will not change during the lifetime of Cat, and which can be read from without side-effects, then Cat may be used directly. Otherwise, it may be a good idea to call ToList() on Cat and use the resulting List<T> (which will represent a snapshot of the contents of A and B).

Some enumerables take a snapshot when enumeration begins, and will return data from that snapshot if the collection is modified during enumeration. If B is such an enumerable, then any change to B which occurs before Cat has reached the end of A will show up in Cat's enumeration, but changes which occur after that will not. Such semantics may likely be confusing; taking a snapshot of Cat can avoid such issues.