I am trying to find some javascript code that will write the current date in this format: mmddyy
Everything I have found uses 4 digit years and I need 2 digit.
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javascript
date
//pull the last two digits of the year_x000D_
//logs to console_x000D_
//creates a new date object (has the current date and time by default)_x000D_
//gets the full year from the date object (currently 2017)_x000D_
//converts the variable to a string_x000D_
//gets the substring backwards by 2 characters (last two characters) _x000D_
console.log(new Date().getFullYear().toString().substr(-2));
_x000D_
JavaScript:
//A function for formatting a date to MMddyy_x000D_
function formatDate(d)_x000D_
{_x000D_
//get the month_x000D_
var month = d.getMonth();_x000D_
//get the day_x000D_
//convert day to string_x000D_
var day = d.getDate().toString();_x000D_
//get the year_x000D_
var year = d.getFullYear();_x000D_
_x000D_
//pull the last two digits of the year_x000D_
year = year.toString().substr(-2);_x000D_
_x000D_
//increment month by 1 since it is 0 indexed_x000D_
//converts month to a string_x000D_
month = (month + 1).toString();_x000D_
_x000D_
//if month is 1-9 pad right with a 0 for two digits_x000D_
if (month.length === 1)_x000D_
{_x000D_
month = "0" + month;_x000D_
}_x000D_
_x000D_
//if day is between 1-9 pad right with a 0 for two digits_x000D_
if (day.length === 1)_x000D_
{_x000D_
day = "0" + day;_x000D_
}_x000D_
_x000D_
//return the string "MMddyy"_x000D_
return month + day + year;_x000D_
}_x000D_
_x000D_
var d = new Date();_x000D_
console.log(formatDate(d));
_x000D_
another version:
var yy = (new Date().getFullYear()+'').slice(-2);
var currentYear = (new Date()).getFullYear();
var twoLastDigits = currentYear%100;
var formatedTwoLastDigits = "";
if (twoLastDigits <10 ) {
formatedTwoLastDigits = "0" + twoLastDigits;
} else {
formatedTwoLastDigits = "" + twoLastDigits;
}
Given a date object:
date.getFullYear().toString().substr(2,2);
It returns the number as string. If you want it as integer just wrap it inside the parseInt() function:
var twoDigitsYear = parseInt(date.getFullYear().toString().substr(2,2), 10);
Example with the current year in one line:
var twoDigitsCurrentYear = parseInt(new Date().getFullYear().toString().substr(2,2));
var d = new Date();
var n = d.getFullYear();
Yes, n will give you the 4 digit year, but you can always use substring or something similar to split up the year, thus giving you only two digits:
var final = n.toString().substring(2);
This will give you the last two digits of the year (2013 will become 13, etc...)
If there's a better way, hopefully someone posts it! This is the only way I can think of. Let us know if it works!
Source: Stackoverflow.com