Abort trap 6 error in C

Question

I have this code   void drawInitialNim int num1  int num2  int num3        int board 2  50     make an array with 3 columns     int i     i  j  k are loop counters     int j      int k       for i 0 i lt num1 1 i           fill the array with rocks  or  O          board 0  i     O         for example  if num1 is 5  fill the first row with 5 rocks     for  i 0  i lt num2 1  i            board 1  i     O       for  i 0  i lt num3 1  i            board 2  i     O        for  j 0  j lt 2 j              print the array       for  k 0  k lt 50 k               printf   d  board j  k                     return     int main         int numRock1 numRock2 numRock3      numRock1   0      numRock2   0      numRock3   0       printf  Welcome to Nim  n        printf  Enter the number of rocks in each row          scanf   d  d  d    amp numRock1   amp numRock2   amp numRock3       drawInitialNim numRock1  numRock2  numRock3     call the function      return 0      When I compile this with gcc  it is fine  When I run the file  I get the abort trap 6 error after entering the values    I have looked at other posts about this error  and they don t help me

User · Accepted Answer

Try this   void drawInitialNim int num1  int num2  int num3       int board 3  50     0      This is a local variable  It is not possible to use it after returning from this function        int i  j  k       for i 0  i lt num1  i            board 0  i     O       for i 0  i lt num2  i            board 1  i     O       for i 0  i lt num3  i            board 2  i     O        for  j 0  j lt 3 j              for  k 0  k lt 50  k                  if board j  k     0                  printf   c   board j  k                      printf   n

User · Answer

You are writing to memory you do not own     int board 2  50     make an array with 3 columns   wrong                       actually makes an array with only two  columns       for  i 0  i lt num3 1  i        board 2  i     O                 Change this line   int board 2  50     array with 2 columns  legal indices  0-1  0-49                 To    int board 3  50     array with 3 columns  legal indices  0-2  0-49                 When creating an array  the value used to initialize   3  indicates array size  However  when accessing existing array elements  index values are zero based     For an array created   int board 3  50   Legal indices are board 0  0    board 2  49      EDIT  To address bad output comment and initialization comment    add an additional   n  for formatting output   Change             for  k 0  k lt 50 k           printf   d  board j  k                         To           for  k 0  k lt 50 k           printf   d  board j  k          printf   n     at the end of every row  print a new line           Initialize board variable     int board 3  50     0    initialize all elements to zero     array initialization discussion

[c] Abort trap 6 error in C

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