How to solve Notice Undefined index id in C xampp htdocs invmgt manufactured goods change php on line 21

Question

I have a problem with my PHP code saying that  Notice  Undefined index  I am sure its very simple  since I am a beginner i am not getting well what is wrong exactly so please help me   Here s the code   lt  php require once     Connections itemconn php      gt       lt  php          id   GET  id               query mysql query  select   from manuf where id   id    or die mysql error              row mysql fetch array  query              gt    lt form action  updateprice php  method  post  enctype  multipart form-data  gt     lt table align  center  gt      lt tr gt      lt td gt   lt label gt  lt strong gt Item Name lt  strong gt  lt  label gt  lt  td gt        lt td gt   lt label gt   lt  php echo  row  itemname      gt  lt  label gt  lt input type  hidden  name  id  value   lt  php echo  id    gt      gt        lt br   gt  lt  td gt       lt  tr gt       lt tr gt         lt td gt  lt label gt  lt strong gt Unit price  lt  strong gt  lt  label gt  lt  td gt     lt td gt   lt input type  text  name  pass  value   lt  php echo  row  unitprice      gt      gt  lt br   gt  lt  td gt     lt  tr gt        lt tr gt     lt td gt              lt input type  reset  name  Reset  value  CANCEL    gt         lt br gt  lt  td gt          lt td gt              lt input type  submit  name  Submit2  value  Update    gt        lt  td gt      lt  tr gt   lt  table gt   lt  form gt   lt  body gt   lt  html gt

User · Accepted Answer

You are not getting value of  id   GET  id     And you are using it  before it gets initialised    Use php s in built isset   function to check whether the variable is  defied or not   So  please update the line to    id   isset   GET  id        GET  id

User · Answer

Simply add this   id        if  isset    GET  id            id     GET  id

User · Answer

if you are getting id from url try   id    isset   GET  id        GET  id            if getting from form you need to use POST method cause your form has method  post     id    isset   POST  id        POST  id            For php notices use isset   or empty   to check values exist or not or initialize variable first with blank or a value   id

[php] How to solve Notice: Undefined index: id in C:\xampp\htdocs\invmgt\manufactured_goods\change.php on line 21

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