[c++] Convert Mat to Array/Vector in OpenCV

None of the provided examples here work for the generic case, which are N dimensional matrices. Anything using "rows" assumes theres columns and rows only, a 4 dimensional matrix might have more.

Here is some example code copying a non-continuous N-dimensional matrix into a continuous memory stream - then converts it back into a Cv::Mat

#include <iostream>
#include <cstdint>
#include <cstring>
#include <opencv2/opencv.hpp>

int main(int argc, char**argv)
{
    if ( argc != 2 )
    {
        std::cerr << "Usage: " << argv[0] << " <Image_Path>\n";
        return -1;
    }
    cv::Mat origSource = cv::imread(argv[1],1);

    if (!origSource.data) {
        std::cerr << "Can't read image";
        return -1;
    }

    // this will select a subsection of the original source image - WITHOUT copying the data
    // (the header will point to a region of interest, adjusting data pointers and row step sizes)
    cv::Mat sourceMat = origSource(cv::Range(origSource.size[0]/4,(3*origSource.size[0])/4),cv::Range(origSource.size[1]/4,(3*origSource.size[1])/4));

    // correctly copy the contents of an N dimensional cv::Mat
    // works just as fast as copying a 2D mat, but has much more difficult to read code :)
    // see http://stackoverflow.com/questions/18882242/how-do-i-get-the-size-of-a-multi-dimensional-cvmat-mat-or-matnd
    // copy this code in your own cvMat_To_Char_Array() function which really OpenCV should provide somehow...
    // keep in mind that even Mat::clone() aligns each row at a 4 byte boundary, so uneven sized images always have stepgaps
    size_t totalsize = sourceMat.step[sourceMat.dims-1];
    const size_t rowsize = sourceMat.step[sourceMat.dims-1] * sourceMat.size[sourceMat.dims-1];
    size_t coordinates[sourceMat.dims-1] = {0};
    std::cout << "Image dimensions: ";
    for (int t=0;t<sourceMat.dims;t++)
    {
        // calculate total size of multi dimensional matrix by multiplying dimensions
        totalsize*=sourceMat.size[t];
        std::cout << (t>0?" X ":"") << sourceMat.size[t];
    }
    // Allocate destination image buffer
    uint8_t * imagebuffer = new uint8_t[totalsize];
    size_t srcptr=0,dptr=0;
    std::cout << std::endl;
    std::cout << "One pixel in image has " << sourceMat.step[sourceMat.dims-1] << " bytes" <<std::endl;
    std::cout << "Copying data in blocks of " << rowsize << " bytes" << std::endl ;
    std::cout << "Total size is " << totalsize << " bytes" << std::endl;
    while (dptr<totalsize) {
        // we copy entire rows at once, so lowest iterator is always [dims-2]
        // this is legal since OpenCV does not use 1 dimensional matrices internally (a 1D matrix is a 2d matrix with only 1 row)
        std::memcpy(&imagebuffer[dptr],&(((uint8_t*)sourceMat.data)[srcptr]),rowsize);
        // destination matrix has no gaps so rows follow each other directly
        dptr += rowsize;
        // src matrix can have gaps so we need to calculate the address of the start of the next row the hard way
        // see *brief* text in opencv2/core/mat.hpp for address calculation
        coordinates[sourceMat.dims-2]++;
        srcptr = 0;
        for (int t=sourceMat.dims-2;t>=0;t--) {
            if (coordinates[t]>=sourceMat.size[t]) {
                if (t==0) break;
                coordinates[t]=0;
                coordinates[t-1]++;
            }
            srcptr += sourceMat.step[t]*coordinates[t];
        }
   }

   // this constructor assumes that imagebuffer is gap-less (if not, a complete array of step sizes must be given, too)
   cv::Mat destination=cv::Mat(sourceMat.dims, sourceMat.size, sourceMat.type(), (void*)imagebuffer);

   // and just to proof that sourceImage points to the same memory as origSource, we strike it through
   cv::line(sourceMat,cv::Point(0,0),cv::Point(sourceMat.size[1],sourceMat.size[0]),CV_RGB(255,0,0),3);

   cv::imshow("original image",origSource);
   cv::imshow("partial image",sourceMat);
   cv::imshow("copied image",destination);
   while (cv::waitKey(60)!='q');
}

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