[python] Access IP Camera in Python OpenCV

How do I access my IP Camera stream?

Code for displaying a standard webcam stream is

import cv2
import numpy as np

cap = cv2.VideoCapture(0)

while(True):
    ret, frame = cap.read()
    cv2.imshow('frame',frame)
    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

cap.release()
cv2.destroyAllWindows()

How do I do the same exact thing but with the IP Camera?

My system:

  • Python 2.7.14
  • OpenCV 2.4.9
  • Teledyne Dalsa Genie Nano XL Camera

Help will be highly appreciated

You can use video capture Object as

camera = cv2.VideoCapture("IP:PORT/video")

This question is related to python opencv ip-camera

The answer is


An IP camera can be accessed in opencv by providing the streaming URL of the camera in the constructor of cv2.VideoCapture.

Usually, RTSP or HTTP protocol is used by the camera to stream video. An example of IP camera streaming URL is as follows:

rtsp://192.168.1.64/1

It can be opened with OpenCV like this:

capture = cv2.VideoCapture('rtsp://192.168.1.64/1')

Most of the IP cameras have a username and password to access the video. In such case, the credentials have to be provided in the streaming URL as follows:

capture = cv2.VideoCapture('rtsp://username:[email protected]/1')

To access an Ip Camera, first, I recommend you to install it like you are going to use for the standard application, without any code, using normal software.

After this, you have to know that for different cameras, we have different codes. There is a website where you can see what code you can use to access them:

https://www.ispyconnect.com/sources.aspx

But be careful, for my camera (Intelbras S3020) it does not work. The right way is to ask the company of your camera, and if they are a good company they will provide it.

When you know your code just add it like:

cap = cv2.VideoCapture("http://LOGIN:PASSWORD@IP/cgi-bin/mjpg/video.cgi?&subtype=1")

Instead LOGIN you will put your login, and instead PASSWORD you will put your password.

To find out camera's IP address there is many softwares that you can download and provide the Ip address to you. I use the software from Intelbras, but I also recommend EseeCloud because they work for almost all cameras that I've bought:

https://eseecloud.software.informer.com/1.2/

In this example, it shows the protocol http to access the Ip camera, but you can also use rstp, it depends on the camera, as I said.

If you have any further questions just let me know.


Getting the correct URL for your camera seems to be the actual challenge! I'm putting my working URL here, it might help someone. The camera is EZVIZ C1C with exact model cs-c1c-d0-1d2wf. The working URL is

rtsp://admin:[email protected]/h264_stream

where SZGBZT is the verification code found at the bottom of the camera. admin is always admin regardless of any settings or users you have.

The final code will be

video_capture = cv2.VideoCapture('rtsp://admin:[email protected]/h264_stream')

You can access most IP cameras using the method below.

import cv2 

# insert the HTTP(S)/RSTP feed from the camera
url = "http://username:password@your_ip:your_port/tmpfs/auto.jpg"

# open the feed
cap = cv2.VideoCapture(url)

while True:
    # read next frame
     ret, frame = cap.read()
    
    # show frame to user
     cv2.imshow('frame', frame)
    
    # if user presses q quit program
     if cv2.waitKey(1) & 0xFF == ord("q"):
        break

# close the connection and close all windows
cap.release()
cv2.destroyAllWindows()

In pycharm I wrote the code for accessing the IP Camera like:

import cv2

cap=VideoCapture("rtsp://user_name:password@IP_address:port_number")

ret, frame=cap.read()

You will need to replace user_name, password, IP and port with suitable values


The easiest way to stream video via IP Camera !

I just edit your example. You must replace your IP and add /video on your link. And go ahead with your project

import cv2

cap = cv2.VideoCapture('http://192.168.18.37:8090/video')

while(True):
    ret, frame = cap.read()
    cv2.imshow('frame',frame)
    if cv2.waitKey(1) & 0xFF == ord('q'):
        cv2.destroyAllWindows()
        break

This works with my IP camera:

import cv2

#print("Before URL")
cap = cv2.VideoCapture('rtsp://admin:[email protected]/H264?ch=1&subtype=0')
#print("After URL")

while True:

    #print('About to start the Read command')
    ret, frame = cap.read()
    #print('About to show frame of Video.')
    cv2.imshow("Capturing",frame)
    #print('Running..')

    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

cap.release()
cv2.destroyAllWindows()

I found the Stream URL in the Camera's Setup screen: IP Camera Setup Screen

Note that I added the Username (admin) and Password (123456) of the camera and ended it with an @ symbol before the IP address in the URL (admin:123456@)


For getting the IP Camera video link:

  1. Open the IP Camera with given IP and PORT in browser
  2. Right click the video and select "copy image address"
  3. Use that address to capture video

First find out your IP camera's streaming url, like whether it's RTSP/HTTP etc.

Code changes will be as follows:

cap = cv2.VideoCapture("ipcam_streaming_url")

For example:

cap = cv2.VideoCapture("http://192.168.18.37:8090/test.mjpeg")

As mentioned above by @Gustavo GeoDrones you can find your Cam URL using https://www.ispyconnect.com/sources.aspx.

Go to the website, click on the model of your camera and a "Cam Video URL Generator" will appear. Insert your IP, username, etc. and click on "generate".

Cam URL for my Canon VB-H45 is (of course with my specific username, password and IP):

http://username:password@IP/-wvhttp-01-/video.cgi

The final code:

cap = cv2.VideoCapture('http://username:password@IP/-wvhttp-01-/video.cgi')