TypeError list object cannot be interpreted as an integer

Question

The playSound function is taking a list of integers  and is going to play a sound for every different number  So if one of the numbers in the list is 1  1 has a designated sound that it will play    def userNum iterations     myList        for i in range iterations       a   int input  Enter a number for sound          myList append a      return myList   print myList   def playSound myList     for i in range myList       if i    1        winsound PlaySound  SystemExit   winsound SND ALIAS    I am getting this error   TypeError   list  object cannot be interpreted as an integer   I have tried a few ways to convert the list to integers  I am not too sure what I need to change  I am sure that there is a more efficient way of doing this  Any help would be very greatly appreciated

User · Answer

Error messages usually mean precisely what they say   So they must be read very carefully   When you do that  you ll see that this one is not actually complaining  as you seem to have assumed  about what sort of object your list contains  but rather about what sort of object it is   It s not saying it wants your list to contain integers  plural    instead  it seems to want your list to be an integer  singular  rather than a list of anything  And since you can t  convert a list into a single integer  at least  not in a way that is meaningful in this context  you shouldn t be trying   So the question is   why does the interpreter seem to want to interpret your list as an integer   The answer is that you are passing your list as the input argument to range  which expects an integer   Don t do that   Say for i in myList instead

User · Answer

For me i was getting this error because i needed to put the arrays in paratheses  The error is a bit tricky in this case    ie  concatenate  a  b   is right not concatenate a  b  hope that helps

User · Answer

remove the range    for i in myList   range takes in an integer  you want for each element in the list

User · Answer

The error is from this   def playSound myList     for i in range myList      lt   myList is a list  not an integer   You cannot pass a list to range which expects an integer  Most likely  you meant to do    def playSound myList     for list item in myList    OR   def playSound myList     for i in range len myList      OR   def playSound myList     for i  list item in enumerate myList

User · Answer

range is expecting an integer argument  from which it will build a range of integers    gt  gt  gt  range 10  range 0  10   gt  gt  gt  list range 10    0  1  2  3  4  5  6  7  8  9   gt  gt  gt    Moreover  giving it a list will raise a TypeError because range will not know how to handle it    gt  gt  gt  range  1  2  3   Traceback  most recent call last     File   lt stdin gt    line 1  in  lt module gt  TypeError   list  object cannot be interpreted as an integer  gt  gt  gt      If you want to access the items in myList  loop over the list directly   for i in myList            Demo    gt  gt  gt  myList    1  2  3   gt  gt  gt  for i in myList          print i      1 2 3  gt  gt  gt

User · Answer

def userNum iterations       myList          for i in range iterations           a   int input  Enter a number for sound              myList append a      print myList    print before return     return myList   return outside of loop  def playSound myList       for i in range len myList      range takes int not list         if i    1              winsound PlaySound  SystemExit   winsound SND ALIAS

User · Answer

since it s a list it cannot be taken directly into range function as the singular integer value of the list is missing  use this for i in range len myList    with this  we get the singular integer value which can be used easily

User · Answer

In playSound    instead of  for i in range myList     try  for i in myList    This will iterate over the contents of myList  which I believe is what you want  range myList  doesn t make any sense

User · Answer

You should do this instead   for i in myList        etc    That is  remove the range   part  The range   function is used to generate a sequence of numbers  and it receives as parameters the limits to generate the range  it won t work to pass a list as parameter  For iterating over the list  just write the loop as shown above

[python] TypeError: 'list' object cannot be interpreted as an integer

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