I am having trouble with the following piece of code:
if verb == "stoke":
if items["furnace"] >= 1:
print("going to stoke the furnace")
if items["coal"] >= 1:
print("successful!")
temperature += 250
print("the furnace is now " + (temperature) + "degrees!")
^this line is where the issue is occuring
else:
print("you can't")
else:
print("you have nothing to stoke")
The resulting error comes up as the following:
Traceback(most recent call last):
File "C:\Users\User\Documents\Python\smelting game 0.3.1 build
incomplete.py"
, line 227, in <module>
print("the furnace is now " + (temperature) + "degrees!")
TypeError: must be str, not int
I am unsure what the problem is as i have changed the name from temp to temperature and added the brackets around temperature but still the error occurs.
This question is related to
python
python-3.6
typeerror
Python comes with numerous ways of formatting strings:
New style .format()
, which supports a rich formatting mini-language:
>>> temperature = 10
>>> print("the furnace is now {} degrees!".format(temperature))
the furnace is now 10 degrees!
Old style %
format specifier:
>>> print("the furnace is now %d degrees!" % temperature)
the furnace is now 10 degrees!
In Py 3.6 using the new f""
format strings:
>>> print(f"the furnace is now {temperature} degrees!")
the furnace is now 10 degrees!
Or using print()
s default sep
arator:
>>> print("the furnace is now", temperature, "degrees!")
the furnace is now 10 degrees!
And least effectively, construct a new string by casting it to a str()
and concatenating:
>>> print("the furnace is now " + str(temperature) + " degrees!")
the furnace is now 10 degrees!
Or join()
ing it:
>>> print(' '.join(["the furnace is now", str(temperature), "degrees!"]))
the furnace is now 10 degrees!
you need to cast int to str before concatenating. for that use str(temperature)
. Or you can print the same output using ,
if you don't want to convert like this.
print("the furnace is now",temperature , "degrees!")
Source: Stackoverflow.com