[bash] How to replace ${} placeholders in a text file?

Here's a robust Bash function that - despite using eval - should be safe to use.

All ${varName} variable references in the input text are expanded based on the calling shell's variables.

Nothing else is expanded: neither variable references whose names are not enclosed in {...} (such as $varName), nor command substitutions ($(...) and legacy syntax `...`), nor arithmetic substitutions ($((...)) and legacy syntax $[...]).

To treat a $ as a literal, \-escape it; e.g.:\${HOME}

Note that input is only accepted via stdin.

Example:

$ expandVarsStrict <<<'$HOME is "${HOME}"; `date` and \$(ls)' # only ${HOME} is expanded
$HOME is "/Users/jdoe"; `date` and $(ls)

Function source code:

expandVarsStrict(){
  local line lineEscaped
  while IFS= read -r line || [[ -n $line ]]; do  # the `||` clause ensures that the last line is read even if it doesn't end with \n
    # Escape ALL chars. that could trigger an expansion..
    IFS= read -r -d '' lineEscaped < <(printf %s "$line" | tr '`([$' '\1\2\3\4')
    # ... then selectively reenable ${ references
    lineEscaped=${lineEscaped//$'\4'{/\${}
    # Finally, escape embedded double quotes to preserve them.
    lineEscaped=${lineEscaped//\"/\\\"}
    eval "printf '%s\n' \"$lineEscaped\"" | tr '\1\2\3\4' '`([$'
  done
}

The function assumes that no 0x1, 0x2, 0x3, and 0x4 control characters are present in the input, because those chars. are used internally - since the function processes text, that should be a safe assumption.

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