How to subtract a day from a date

Question

I have a Python datetime datetime object  What is the best way to subtract one day

User · Accepted Answer

You can use a timedelta object  from datetime import datetime  timedelta      d   datetime today   - timedelta days days to subtract

User · Answer

Genial arrow module exists  import arrow utc   arrow utcnow   utc yesterday   utc shift days -1  print utc    n   utc yesterday    output   2017-04-06T11 17 34 431397 00 00   2017-04-05T11 17 34 431397 00 00

User · Answer

Subtract datetime timedelta days 1

User · Answer

Just to Elaborate an alternate method and a Use case for which it is helpful    Subtract 1 day from current datetime     from datetime import datetime  timedelta print datetime now     timedelta days -1     Here  I am adding a negative timedelta     Useful in the Case  If you want to add 5 days and subtract 5 hours from current datetime  i e  What is the Datetime 5 days from now but 5 hours less      from datetime import datetime  timedelta print datetime now     timedelta days 5  hours -5     It can similarly be used with other parameters e g  seconds  weeks etc

User · Answer

If your Python datetime object is timezone-aware than you should be careful to avoid errors around DST transitions  or changes in UTC offset for other reasons    from datetime import datetime  timedelta from tzlocal import get localzone   pip install tzlocal  DAY   timedelta 1  local tz   get localzone       get local timezone now   datetime now local tz    get timezone-aware datetime object day ago   local tz normalize now - DAY    exactly 24 hours ago  time may differ naive   now replace tzinfo None  - DAY   same time yesterday   local tz localize naive  is dst None    but elapsed hours may differ   In general  day ago and yesterday may differ if UTC offset for the local timezone has changed in the last day   For example   daylight saving time summer time ends on Sun 2-Nov-2014 at 02 00 00 A M  in America Los Angeles timezone therefore if   import pytz   pip install pytz  local tz   pytz timezone  America Los Angeles   now   local tz localize datetime 2014  11  2  10   is dst None    2014-11-02 10 00 00 PST-0800   then day ago and yesterday differ     day ago is exactly 24 hours ago  relative to now  but at 11 am  not at 10 am as now yesterday is yesterday at 10 am but it is 25 hours ago  relative to now   not 24 hours      pendulum module handles it automatically    gt  gt  gt  import pendulum      pip install pendulum   gt  gt  gt  now   pendulum create 2014  11  2  10  tz  America Los Angeles    gt  gt  gt  day ago   now subtract hours 24     exactly 24 hours ago  gt  gt  gt  yesterday   now subtract days 1     yesterday at 10 am but it is 25 hours ago   gt  gt  gt   now - day ago  in hours   24  gt  gt  gt   now - yesterday  in hours   25   gt  gt  gt  now  lt Pendulum  2014-11-02T10 00 00-08 00  gt   gt  gt  gt  day ago  lt Pendulum  2014-11-01T11 00 00-07 00  gt   gt  gt  gt  yesterday  lt Pendulum  2014-11-01T10 00 00-07 00  gt

User · Answer

Genial arrow module exists  import arrow utc   arrow utcnow   utc yesterday   utc shift days -1  print utc    n   utc yesterday    output   2017-04-06T11 17 34 431397 00 00   2017-04-05T11 17 34 431397 00 00

User · Answer

If your Python datetime object is timezone-aware than you should be careful to avoid errors around DST transitions  or changes in UTC offset for other reasons    from datetime import datetime  timedelta from tzlocal import get localzone   pip install tzlocal  DAY   timedelta 1  local tz   get localzone       get local timezone now   datetime now local tz    get timezone-aware datetime object day ago   local tz normalize now - DAY    exactly 24 hours ago  time may differ naive   now replace tzinfo None  - DAY   same time yesterday   local tz localize naive  is dst None    but elapsed hours may differ   In general  day ago and yesterday may differ if UTC offset for the local timezone has changed in the last day   For example   daylight saving time summer time ends on Sun 2-Nov-2014 at 02 00 00 A M  in America Los Angeles timezone therefore if   import pytz   pip install pytz  local tz   pytz timezone  America Los Angeles   now   local tz localize datetime 2014  11  2  10   is dst None    2014-11-02 10 00 00 PST-0800   then day ago and yesterday differ     day ago is exactly 24 hours ago  relative to now  but at 11 am  not at 10 am as now yesterday is yesterday at 10 am but it is 25 hours ago  relative to now   not 24 hours      pendulum module handles it automatically    gt  gt  gt  import pendulum      pip install pendulum   gt  gt  gt  now   pendulum create 2014  11  2  10  tz  America Los Angeles    gt  gt  gt  day ago   now subtract hours 24     exactly 24 hours ago  gt  gt  gt  yesterday   now subtract days 1     yesterday at 10 am but it is 25 hours ago   gt  gt  gt   now - day ago  in hours   24  gt  gt  gt   now - yesterday  in hours   25   gt  gt  gt  now  lt Pendulum  2014-11-02T10 00 00-08 00  gt   gt  gt  gt  day ago  lt Pendulum  2014-11-01T11 00 00-07 00  gt   gt  gt  gt  yesterday  lt Pendulum  2014-11-01T10 00 00-07 00  gt

User · Answer

Subtract datetime timedelta days 1

User · Answer

Subtract datetime timedelta days 1

User · Answer

Also just another nice function i like to use when i want to compute i e  first last day of the last month or other relative timedeltas etc       The relativedelta function from dateutil function  a powerful extension to the datetime lib   import datetime as dt from dateutil relativedelta import relativedelta  get first and last day of this and last month  today   dt date today   first day this month   dt date day 1  month today month  year today year  last day last month   first day this month - relativedelta days 1  print  first day this month  last day last month    gt 2015-03-01 2015-02-28

User · Answer

Subtract datetime timedelta days 1

User · Answer

Also just another nice function i like to use when i want to compute i e  first last day of the last month or other relative timedeltas etc       The relativedelta function from dateutil function  a powerful extension to the datetime lib   import datetime as dt from dateutil relativedelta import relativedelta  get first and last day of this and last month  today   dt date today   first day this month   dt date day 1  month today month  year today year  last day last month   first day this month - relativedelta days 1  print  first day this month  last day last month    gt 2015-03-01 2015-02-28

User · Answer

Just to Elaborate an alternate method and a Use case for which it is helpful    Subtract 1 day from current datetime     from datetime import datetime  timedelta print datetime now     timedelta days -1     Here  I am adding a negative timedelta     Useful in the Case  If you want to add 5 days and subtract 5 hours from current datetime  i e  What is the Datetime 5 days from now but 5 hours less      from datetime import datetime  timedelta print datetime now     timedelta days 5  hours -5     It can similarly be used with other parameters e g  seconds  weeks etc

[python] How to subtract a day from a date?

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