[python] How to remove duplicates from Python list and keep order?

Given a list of strings, I want to sort it alphabetically and remove duplicates. I know I can do this:

from sets import Set
[...]
myHash = Set(myList)

but I don't know how to retrieve the list members from the hash in alphabetical order.

I'm not married to the hash, so any way to accomplish this will work. Also, performance is not an issue, so I'd prefer a solution that is expressed in code clearly to a fast but more opaque one.

If your input is already sorted, then there may be a simpler way to do it:

from operator import itemgetter
from itertools import groupby
unique_list = list(map(itemgetter(0), groupby(yourList)))

If it's clarity you're after, rather than speed, I think this is very clear:

def sortAndUniq(input):
  output = []
  for x in input:
    if x not in output:
      output.append(x)
  output.sort()
  return output

It's O(n^2) though, with the repeated use of not in for each element of the input list.

If it's clarity you're after, rather than speed, I think this is very clear:

def sortAndUniq(input):
  output = []
  for x in input:
    if x not in output:
      output.append(x)
  output.sort()
  return output

It's O(n^2) though, with the repeated use of not in for each element of the input list.

For the string data

 output = []

     def uniq(input):
         if input not in output:
            output.append(input)
 print output     

If you want to keep order of the original list, just use OrderedDict with None as values.

In Python2:

    from collections import OrderedDict
    from itertools import izip, repeat

    unique_list = list(OrderedDict(izip(my_list, repeat(None))))

In Python3 it's even simpler:

    from collections import OrderedDict
    from itertools import repeat

    unique_list = list(OrderedDict(zip(my_list, repeat(None))))

If you don't like iterators (zip and repeat) you can use a generator (works both in 2 & 3):

    from collections import OrderedDict
    unique_list = list(OrderedDict((element, None) for element in my_list))

If it's clarity you're after, rather than speed, I think this is very clear:

def sortAndUniq(input):
  output = []
  for x in input:
    if x not in output:
      output.append(x)
  output.sort()
  return output

It's O(n^2) though, with the repeated use of not in for each element of the input list.

For the string data

 output = []

     def uniq(input):
         if input not in output:
            output.append(input)
 print output     

If it's clarity you're after, rather than speed, I think this is very clear:

def sortAndUniq(input):
  output = []
  for x in input:
    if x not in output:
      output.append(x)
  output.sort()
  return output

It's O(n^2) though, with the repeated use of not in for each element of the input list.

> but I don't know how to retrieve the list members from the hash in alphabetical order.

Not really your main question, but for future reference Rod's answer using sorted can be used for traversing a dict's keys in sorted order:

for key in sorted(my_dict.keys()):
   print key, my_dict[key]
   ...

and also because tuple's are ordered by the first member of the tuple, you can do the same with items:

for key, val in sorted(my_dict.items()):
    print key, val
    ...

> but I don't know how to retrieve the list members from the hash in alphabetical order.

Not really your main question, but for future reference Rod's answer using sorted can be used for traversing a dict's keys in sorted order:

for key in sorted(my_dict.keys()):
   print key, my_dict[key]
   ...

and also because tuple's are ordered by the first member of the tuple, you can do the same with items:

for key, val in sorted(my_dict.items()):
    print key, val
    ...

If your input is already sorted, then there may be a simpler way to do it:

from operator import itemgetter
from itertools import groupby
unique_list = list(map(itemgetter(0), groupby(yourList)))

If you want to keep order of the original list, just use OrderedDict with None as values.

In Python2:

    from collections import OrderedDict
    from itertools import izip, repeat

    unique_list = list(OrderedDict(izip(my_list, repeat(None))))

In Python3 it's even simpler:

    from collections import OrderedDict
    from itertools import repeat

    unique_list = list(OrderedDict(zip(my_list, repeat(None))))

If you don't like iterators (zip and repeat) you can use a generator (works both in 2 & 3):

    from collections import OrderedDict
    unique_list = list(OrderedDict((element, None) for element in my_list))