YYYY-MM-DD format date in shell script

Question

I tried using   date  in my bash shell script  however  I want the date in YYYY-MM-DD format  How do I get this

User · Answer

You can do something like this     date    Y- m- d

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You re looking for ISO 8601 standard date format  so if you have GNU date  or any date command more modern than 1988  just do    date -I

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date   F  H- M- S    can be used to remove colons     in between  output  2018-06-20 09-55-58

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Whenever I have a task like this I end up falling back to   man strftime  to remind myself of all the possibilities for time formatting options

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In bash    4 2  it is preferable to use printf s built-in date formatter  part of bash  rather than the external date  usually GNU date    As such     put current date as yyyy-mm-dd in  date   -1 - gt  explicit current date  bash  gt  4 3 defaults to current time if not provided   -2 - gt  start time for shell printf -v date     Y- m- d T n  -1     put current date as yyyy-mm-dd HH MM SS in  date printf -v date     Y- m- d  H  M  S T n  -1     to print directly remove -v flag  as such  printf     Y- m- d T n  -1   - gt  current date printed to terminal   In bash   lt 4 2       put current date as yyyy-mm-dd in  date date   date    Y- m- d      put current date as yyyy-mm-dd HH MM SS in  date date   date    Y- m- d  H  M  S      print current date directly echo   date    Y- m- d     Other available date formats can be viewed from the date man pages  for external non-bash specific command    man date

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With recent Bash  version   4 2   you can use the builtin printf with the format modifier   strftime format T     printf     Y- m- d T n  -1    Get YYYY-MM-DD  -1 stands for  current time   2017-11-10   printf     F T n  -1    Synonym of the above 2017-11-10   printf -v date     F T  -1    Capture as var  date   printf is much faster than date since it s a Bash builtin while date is an external command   As well  printf -v date     is faster than date   printf      since it doesn t require forking a subshell

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Try    date   F

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date -d  1 hour ago     Y- m- d    The output would be 2015-06-14

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I use   date    Y- m- d    or   date    Y- m- d  T   with time and hours

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Try to use this command   date   cut -d  quot   quot  -f2-4   tr  quot   quot   quot - quot    The output would be like  21-Feb-2021

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I use the following formulation   TODAY  date -I  echo  TODAY   Checkout the man page for date  there is a number of other useful options   man date

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You can set date as environment variable and later u can use it  setenv DATE  date    Y- m- d   echo  -----------   DATE  -------------    or   DATE   date    Y- m- d   echo  -----------   DATE  -------------

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bin bash -e  x  2018-01-18 10 00 00  a   date -d   x   b   date -d   a 10 min     Y- m- d  H  M  S   c   date -d   b 10 min     Y- m- d  H  M  S    date -d   a 30 min     Y- m- d  H  M  S   echo Entered Date is  x echo Second Date is  b echo Third Date is  c   Here x is sample date used  amp  then example displays both formatting of data as well as getting dates 10 mins more then current date

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if you want the year in a two number format such as 17 rather than 2017  do the following   DATE  date   d- m- y

[bash] YYYY-MM-DD format date in shell script

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