Use a while loop that checks for the truthfulness of the array:
while array:
value = array.pop(0)
# do some calculation here
And it should do it without any errors or funny behaviour.
Never alter the container you're looping on, because iterators on that container are not going to be informed of your alterations and, as you've noticed, that's quite likely to produce a very different loop and/or an incorrect one. In normal cases, looping on a copy of the container helps, but in your case it's clear that you don't want that, as the container will be empty after 50 legs of the loop and if you then try popping again you'll get an exception.
What's anything BUT clear is, what behavior are you trying to achieve, if any?! Maybe you can express your desires with a while
...?
i = 0
while i < len(some_list):
print i,
print some_list.pop(0),
print some_list.pop(0)
This slice syntax makes a copy of the list and does what you want:
l = range(100)
for i in l[:]:
print i,
print l.pop(0),
print l.pop(0)
I guess this is what you want:
l = range(100)
index = 0
for i in l:
print i,
try:
print l.pop(index+1),
print l.pop(index+1)
except:
pass
index += 1
It is quite handy to code when the number of item to be popped is a run time decision. But it runs with very a bad efficiency and the code is hard to maintain.
Try this. It avoids mutating a thing you're iterating across, which is generally a code smell.
for i in xrange(0, 100, 3):
print i
See xrange
.
The general rule of thumb is that you don't modify a collection/array/list while iterating over it.
Use a secondary list to store the items you want to act upon and execute that logic in a loop after your initial loop.
Source: Stackoverflow.com