[sql] Find rows that have the same value on a column in MySQL

In a [member] table, some rows have the same value for the email column.

login_id | email
---------|---------------------
john     | [email protected]
peter    | [email protected]
johnny   | [email protected]
...

Some people used a different login_id but the same email address, no unique constraint was set on this column. Now I need to find these rows and see if they should be removed.

What SQL statement should I use to find these rows? (MySQL 5)

This question is related to sql mysql database

The answer is


select email from mytable group by email having count(*) >1

This works best

Screenshot enter image description here

SELECT RollId, count(*) AS c 
    FROM `tblstudents` 
    GROUP BY RollId 
    HAVING c > 1 
    ORDER BY c DESC

use this if your email column contains empty values

 select * from table where email in (
    select email from table group by email having count(*) > 1 and email != ''
    )

Here is query to find email's which are used for more then one login_id:

SELECT email
FROM table
GROUP BY email
HAVING count(*) > 1

You'll need second (of nested) query to get list of login_id by email.


Get the entire record as you want using the condition with inner select query.

SELECT *
FROM   member
WHERE  email IN (SELECT email
                 FROM   member
                 WHERE  login_id = [email protected]) 

I know this is a very old question but this is more for someone else who might have the same problem and I think this is more accurate to what was wanted.

SELECT * FROM member WHERE email = (Select email From member Where login_id = [email protected]) 

This will return all records that have [email protected] as a login_id value.


First part of accepted answer does not work for MSSQL.
This worked for me:

select email, COUNT(*) as C from table 
group by email having COUNT(*) >1 order by C desc

Thanks guys :-) I used the below because I only cared about those two columns and not so much about the rest. Worked great

  select email, login_id from table
    group by email, login_id
    having COUNT(email) > 1

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