How to split an integer into an array of digits

Question

My integer input is suppose 12345  I want to split and put it into an array as 1  2  3  4  5  How will I be able to do it

User · Answer

Maybe join split    gt  gt  gt  a 12345  gt  gt  gt  list map int     join str a   split      1  2  3  4  5   gt  gt  gt   int i  for i in     join str a   split     1  2  3  4  5   gt  gt  gt     str join   str split is your friend  also we use map or list comprehension to get a list   split what we join  -

User · Answer

Splitting a single number to it s digits  as answered by all     gt  gt  gt   int i  for i in str 12345    1  2  3  4  5    But  to get digits from a list of numbers    gt  gt  gt   int d  for d in    join str x  for x in  12  34  5     1  2  3  4  5    So like to know  if we can do the above  more efficiently

User · Answer

Strings are just as iterable as arrays  so just convert it to string   str 12345

User · Answer

While list map int  str x    is the Pythonic approach  you can formulate logic to derive digits without any type conversion   from math import log10  def digitize x       n   int log10 x       for i in range n  -1  -1           factor   10  i         k   x    factor         yield k         x -  k   factor  res   list digitize 5243     5  2  4  3    One benefit of a generator is you can feed seamlessly to set  tuple  next  etc  without any additional logic

User · Answer

I d rather not turn an integer into a string  so here s the function I use for this   def digitize n  base 10       if n    0          yield 0     while n          n  d   divmod n  base          yield d   Examples   tuple digitize 123456789       9  8  7  6  5  4  3  2  1  tuple digitize 0b1101110  2       0  1  1  1  0  1  1  tuple digitize 0x123456789ABCDEF  16       15  14  13  12  11  10  9  8  7  6  5  4  3  2  1    As you can see  this will yield digits from right to left  If you d like the digits from left to right  you ll need to create a sequence out of it  then reverse it   reversed tuple digitize x      You can also use this function for base conversion as you split the integer  The following example splits a hexadecimal number into binary nibbles as tuples   import itertools as it tuple it zip longest   digitize 0x123456789ABCDEF  2   4  fillvalue 0        1  1  1  1    0  1  1  1    1  0  1  1    0  0  1  1    1  1  0  1    0  1  0  1    1  0  0  1    0  0  0  1    1  1  1  0    0  1  1  0    1  0  1  0    0  0  1  0    1  1  0  0    0  1  0  0    1  0  0  0     Note that this method doesn t handle decimals  but could be adapted to

User · Answer

Another solution that does not involve converting to from strings  from math import log10  def decompose n       if n    0          return  0      b   int log10 n     1     return   n     10    i     10 for i in reversed range b

User · Answer

int i  for i in str number     or  if do not want to use a list comprehension or you want to use a base different from 10   from   future   import division   for compatibility of    between Python 2 and 3 def digits number  base 10       assert number  gt   0     if number    0          return  0      l          while number  gt  0          l append number   base          number   number    base     return l

User · Answer

gt  gt  gt   int i  for i in str 12345     1  2  3  4  5

User · Answer

return array as string   gt  gt  gt  list str 12345     1    2    3    4    5     return array as integer   gt  gt  gt  map int str 12345    1  2  3  4  5

User · Answer

like  nd says but using the built-in function of int to convert to a different base   gt  gt  gt    int i 16  for i in  0123456789ABCDEF     0  1  2  3  4  5  6  7  8  9  10  11  12  13  14  15    gt  gt  gt   int i 2  for i in  100 010 110 111  split     4  2  6  7    I don t know what is the final objective but take a look also inside the decimal module of python for doing stuff like   gt  gt  gt  Decimal  3 1415926535     Decimal  2 7182818285   Decimal  5 85987

[python] How to split an integer into an array of digits?

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