Checking if a website is up via Python

Question

By using python  how can I check if a website is up  From what I read  I need to check the  quot HTTP HEAD quot  and see status code  quot 200 OK quot   but how to do so   Cheers Related  How do you send a HEAD HTTP request in Python

User · Answer

If by up  you simply mean  the server is serving   then you could use cURL  and if you get a response than it s up   I can t give you specific advice because I m not a python programmer  however here is a link to pycurl http   pycurl sourceforge net

User · Answer

from urllib request import Request  urlopen from urllib error import URLError  HTTPError req   Request  http   stackoverflow com   try      response   urlopen req  except HTTPError as e      print  The server couldn  t fulfill the request        print  Error code     e code  except URLError as e      print  We failed to reach a server        print  Reason     e reason  else      print   Website is working fine     Works on Python 3

User · Answer

Hi this class can do speed and up test for your web page with this class    from urllib request import urlopen  from socket import socket  import time    def tcp test server info        cpos   server info find           try           sock   socket            sock connect  server info  cpos   int server info cpos 1               sock close          return True      except Exception as e           return False    def http test server info        try             TODO   we can use this data after to find sub urls up or down    results          startTime   time time            data   urlopen server info  read            endTime   time time            speed   endTime - startTime          return   status     up    speed    str speed        except Exception as e           return   status     down    speed    str -1      def server test test type  server info        if test type lower       tcp            return tcp test server info       elif test type lower       http            return http test server info

User · Answer

You may use requests library to find if website is up i e  status code as 200  import requests url    https   www google com  page   requests get url  print  page status code     gt  gt  200

User · Answer

I think the easiest way to do it is by using Requests module   import requests  def url ok url       r   requests head url      return r status code    200

User · Answer

You can use httplib  import httplib conn   httplib HTTPConnection  www python org   conn request  HEAD        r1   conn getresponse   print r1 status  r1 reason   prints  200 OK   Of course  only if www python org is up

User · Answer

Here s my solution using PycURL and validators  import pycurl  validators   def url exists url               Check if the given URL really exists      param url  str      return  bool             if validators url url           c   pycurl Curl           c setopt pycurl NOBODY  True          c setopt pycurl FOLLOWLOCATION  False          c setopt pycurl CONNECTTIMEOUT  10          c setopt pycurl TIMEOUT  10          c setopt pycurl COOKIEFILE              c setopt pycurl URL  url          try              c perform               response code   c getinfo pycurl RESPONSE CODE              c close               return True if response code  lt  400 else False         except pycurl error as err              errno  errstr   err             raise OSError  An error occurred      format errstr       else          raise ValueError       is not a valid url  format url

User · Answer

If server if down  on python 2 7 x86 windows urllib have no timeout and program go to dead lock  So use urllib2  import urllib2 import socket  def check url  url  timeout 5        try          return urllib2 urlopen url timeout timeout  getcode      200     except urllib2 URLError as e          return False     except socket timeout as e          print False   print check url  http   google fr     True  print check url  http   notexist kc    False

User · Answer

You could try to do this with getcode   from urllib    gt  gt  gt  print urllib urlopen  http   www stackoverflow com   getcode    gt  gt  gt  200   EDIT  For more modern python  i e  python3  use    import urllib request print urllib request urlopen  http   www stackoverflow com   getcode     gt  gt  gt  200

User · Answer

my 2 cents  def getResponseCode url   conn   urllib request urlopen url  return conn getcode    if getResponseCode url     200      print  Wrong URL   else      print  Good URL

User · Answer

The HTTPConnection object from the httplib module in the standard library will probably do the trick for you  BTW  if you start doing anything advanced with HTTP in Python  be sure to check out httplib2  it s a great library

User · Answer

Requests and httplib2 are great options     Using requests  import requests request   requests get value  if request status code    200      return True return False    Using httplib2  import httplib2  try      http   httplib2 Http       response   http request value   HEAD        if int response 0   status       200          return True except      pass return False   If using Ansible  you can use the fetch url function   from ansible module utils basic import AnsibleModule from ansible module utils urls import fetch url  module   AnsibleModule      dict        supports check mode True   try      response  info   fetch url module  url      if info  status      200          return True  except Exception      pass  return False

User · Answer

In my opinion  caisah s answer misses an important part of your question  namely dealing with the server being offline   Still  using requests is my favorite option  albeit as such   import requests  try      requests get url  except requests exceptions ConnectionError      print f URL  url  not reachable

User · Answer

import httplib import socket import re  def is website online host           This function checks to see if a host name has a DNS entry by checking         for socket info  If the website gets something in return           we know it s available to DNS              try          socket gethostbyname host      except socket gaierror          return False     else          return True   def is page available host  path               This function retreives the status code of a website by requesting         HEAD data from the host  This means that it only requests the headers          If the host cannot be reached or something else goes wrong  it returns         False              try          conn   httplib HTTPConnection host          conn request  HEAD   path          if re match    23  d d    str conn getresponse   status                return True     except StandardError          return None

User · Answer

I use requests for this  then it is easy and clean  Instead of print function you can define and call new function  notify via email etc    Try-except block is essential  because if host is unreachable then it will rise a lot of exceptions so you need to catch them all  import requests  URL    quot https   api github com quot   try      response   requests head URL  except Exception as e      print f quot NOT OK   str e   quot   else      if response status code    200          print  quot OK quot       else          print f quot NOT OK  HTTP response code  response status code  quot

[python] Checking if a website is up via Python

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