Handling urllib2 s timeout - Python

Question

I m using the timeout parameter within the urllib2 s urlopen   urllib2 urlopen  http   www example org   timeout 1    How do I tell Python that if the timeout expires a custom error should be raised     Any ideas

User · Answer

In Python 2 7 3   import urllib2 import socket  class MyException Exception       pass  try      urllib2 urlopen  http   example com   timeout   1  except urllib2 URLError as e      print type e      not catch except socket timeout as e      print type e      catched     raise MyException  There was an error   r    e

User · Answer

There are very few cases where you want to use except   Doing this captures any exception  which can be hard to debug  and it captures exceptions including SystemExit and KeyboardInterupt  which can make your program annoying to use    At the very simplest  you would catch urllib2 URLError   try      urllib2 urlopen  http   example com   timeout   1  except urllib2 URLError  e      raise MyException  There was an error   r    e    The following should capture the specific error raised when the connection times out   import urllib2 import socket  class MyException Exception       pass  try      urllib2 urlopen  http   example com   timeout   1  except urllib2 URLError  e        For Python 2 6     if isinstance e reason  socket timeout           raise MyException  There was an error   r    e      else            reraise the original error         raise except socket timeout  e        For Python 2 7     raise MyException  There was an error   r    e

[python] Handling urllib2's timeout? - Python

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