How to cin Space in c

Question

Say we have a code   int main        char a 10      for int i   0  i  lt  10  i                cin gt  gt a i          if a i                    cout lt  lt  It is a space     lt  lt endl          return 0      How to cin a Space symbol from standard input  If you write space  program ignores     Is there any combination of symbols  e g    s  or something like this  that means  Space  that I can use from standard input for my code

User · Answer

include  lt iostream gt   include  lt string gt   int main        std  string a     std  getline std  cin a      for std  string  size type i   0  i  lt  a size      i              if a i                    std  cout lt  lt  It is a space     lt  lt std  endl          return 0

User · Answer

Using cin s    operator will drop leading whitespace and stop input at the first trailing whitespace   To grab an entire line of input  including spaces  try cin getline     To grab one character at a time  you can use cin get

User · Answer

Use cin get   to read the next character   However  for this problem  it is very inefficient to read a character at a time  Use the istream  read   instead   int main        char a 10      cin read a  sizeof a       for int i   0  i  lt  10  i                if a i                    cout lt  lt  It is a space     lt  lt  lt endl          return 0      And use    to check equality  not

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To input AN ENTIRE LINE containing lot of spaces you can use getline cin string variable    eg   string input  getline cin  input     This format captures all the spaces in the sentence untill return is pressed

User · Answer

Try this all four way to take input with space      include lt iostream gt   include lt stdio h gt   using namespace std   void dinput char  a        for int i 0   i                  cin  gt  gt  noskipws  gt  gt  a i           if a i     n                         a i    0               break                      void input char  a          cout lt  lt   nInput string          for int i 0   i                    a i sizeof char   getchar             if   a i sizeof char      n                           a i sizeof char     0               break                        int main         char a 20        cout lt  lt   n1st method n       input a       cout lt  lt a       cout lt  lt   n2nd method n       cin get a 10       cout lt  lt a       cout lt  lt   n3rd method n       cin sync        cin getline a sizeof a        cout lt  lt a       cout lt  lt   n4th method n       dinput a       cout lt  lt a       return 0

User · Answer

I have the same problem and I just used cin getline input 300     noskipws and cin get   sometimes are not easy to use  Since you have the right size of your array try using cin getline   which does not care about any character and read the whole line in specified character count

User · Answer

It skips all whitespace  spaces  tabs  new lines  etc   by default   You can either change its behavior  or use a slightly different mechanism   To change its behavior  use the manipulator noskipws  as follows    cin  gt  gt  noskipws  gt  gt  a i     But  since you seem like you want to look at the individual characters  I d suggest using get  like this prior to your loop   cin get  a  n      Note   get will stop retrieving chars from the stream if it either finds a newline char   n  or after n-1 chars   It stops early so that it can append the null character   0  to the array   You can read more about the istream interface here

User · Answer

I thought I d share the answer that worked for me  The previous line ended in a newline  so most of these answers by themselves didn t work  This did   string title  do     getline cin  title     while  title length    lt  2     That was assuming the input is always at least 2 characters long  which worked for my situation  You could also try simply comparing it to the string   n

[c++] How to cin Space in c++?

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