[c++] How to cin Space in c++?

Say we have a code:

int main()
{
   char a[10];
   for(int i = 0; i < 10; i++)
   {
       cin>>a[i];
       if(a[i] == ' ')
          cout<<"It is a space!!!"<<endl;
   }
   return 0;
}

How to cin a Space symbol from standard input? If you write space, program ignores! :( Is there any combination of symbols (e.g. '\s' or something like this) that means "Space" that I can use from standard input for my code?

To input AN ENTIRE LINE containing lot of spaces you can use getline(cin,string_variable);

eg:

string input;
getline(cin, input);

This format captures all the spaces in the sentence untill return is pressed

#include <iostream>
#include <string>

int main()
{
   std::string a;
   std::getline(std::cin,a);
   for(std::string::size_type i = 0; i < a.size(); ++i)
   {
       if(a[i] == ' ')
          std::cout<<"It is a space!!!"<<std::endl;
   }
   return 0;
}

Using cin's >> operator will drop leading whitespace and stop input at the first trailing whitespace. To grab an entire line of input, including spaces, try cin.getline(). To grab one character at a time, you can use cin.get().

I have the same problem and I just used cin.getline(input,300);.

noskipws and cin.get() sometimes are not easy to use. Since you have the right size of your array try using cin.getline() which does not care about any character and read the whole line in specified character count.

I thought I'd share the answer that worked for me. The previous line ended in a newline, so most of these answers by themselves didn't work. This did:

string title;
do {
  getline(cin, title);
} while (title.length() < 2);

That was assuming the input is always at least 2 characters long, which worked for my situation. You could also try simply comparing it to the string "\n".

Use cin.get() to read the next character.

However, for this problem, it is very inefficient to read a character at a time. Use the istream::read() instead.

int main()
{
   char a[10];
   cin.read(a, sizeof(a));
   for(int i = 0; i < 10; i++)
   {
       if(a[i] == ' ')
          cout<<"It is a space!!!"<<<endl;
   }
   return 0;
}

And use == to check equality, not =.

Try this all four way to take input with space :)

#include<iostream>
#include<stdio.h>

using namespace std;

void dinput(char *a)
{
    for(int i=0;; i++)
    {
        cin >> noskipws >> a[i];
        if(a[i]=='\n')
        {
            a[i]='\0';
            break;
        }
    }
}


void input(char *a)
{
    //cout<<"\nInput string: ";

    for(int i=0;; i++)
    {
        *(a+i*sizeof(char))=getchar();

        if(*(a+i*sizeof(char))=='\n')
        {
            *(a+i*sizeof(char))='\0';
            break;
        }

    }
}



int main()
{
    char a[20];

    cout<<"\n1st method\n";
    input(a);
    cout<<a;

    cout<<"\n2nd method\n";
    cin.get(a,10);
    cout<<a;

    cout<<"\n3rd method\n";
    cin.sync();
    cin.getline(a,sizeof(a));
    cout<<a;

    cout<<"\n4th method\n";
    dinput(a);
    cout<<a;

    return 0;
}