You could also use:
public static bool IsWhiteSpace(string s)
{
return s.Trim().Length == 0;
}
In .Net 4.0, you can also call String.IsNullOrWhitespace
.
You can do one of two things:
^\s*$
; a match means the string is "empty"
^
, $
are the beginning and end of string anchors respectively\s
is a whitespace character*
is zero-or-more repetition of\S
; an occurrence means the string is NOT "empty"
\S
is the negated version of \s
(note the case difference)\S
therefore matches any non-whitespace characterRegexOptions.ECMAScript
, \s
matches things like ellipsis …
I think [ ]{4}
might work in the example where you need to detect 4 spaces.
Same with the rest: [ ]{1}
, [ ]{2}
and [ ]{3}
. If you want to detect an empty string in general, ^[ ]*$
will do.
Create "regular expression to detect empty string", and then inverse it. Invesion of regular language is the regular language. I think regular expression library in what you leverage - should support it, but if not you always can write your own library.
grep --invert-match
What about?
/.*\S.*/
This means
/
= delimiter
.*
= zero or more of anything but newline
\S
= anything except a whitespace (newline, tab, space)
so you get
match anything but newline + something not whitespace + anything but newline
We can also use space in a char class, in an expression similar to one of these:
(?!^[ ]*$)^\S+$
(?!^[ ]*$)^\S{1,}$
(?!^[ ]{0,}$)^\S{1,}$
(?!^[ ]{0,1}$)^\S{1,}$
depending on the language/flavor that we might use.
using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(?!^[ ]*$)^\S+$";
string input = @"
abcd
ABCD1234
#$%^&*()_+={}
abc def
ABC 123
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
If you wish to simplify/modify/explore the expression, it's been explained on the top right panel of regex101.com. If you'd like, you can also watch in this link, how it would match against some sample inputs.
jex.im visualizes regular expressions:
Assertions are not necessary for this. \S
should work by itself as it matches any non-whitespace.
Source: Stackoverflow.com