I want to create a clone of the structure of our multi-terabyte file server. I know that cp --parents can move a file and it's parent structure, but is there any way to copy the directory structure intact?
I want to copy to a linux system and our file server is CIFS mounted there.
This copy the directories and files attributes, but not the files data:
cp -R --attributes-only SOURCE DEST
Then you can delete the files attributes if you are not interested in them:
find DEST -type f -exec rm {} \;
Substitute target_dir
and source_dir
with the appropriate values:
cd target_dir && (cd source_dir; find . -type d ! -name .) | xargs -i mkdir -p "{}"
Tested on OSX+Ubuntu.
1 line solution:
find . -type d -exec mkdir -p /path/to/copy/directory/tree/{} \;
This works:
find ./<SOURCE_DIR>/ -type d | sed 's/\.\/<SOURCE_DIR>//g' | xargs -I {} mkdir -p <DEST_DIR>"/{}"
Just replace SOURCE_DIR and DEST_DIR.
A python script from Sergiy Kolodyazhnyy posted on Copy only folders not files?:
#!/usr/bin/env python
import os,sys
dirs=[ r for r,s,f in os.walk(".") if r != "."]
for i in dirs:
os.makedirs(os.path.join(sys.argv[1],i))
or from the shell:
python -c 'import os,sys;dirs=[ r for r,s,f in os.walk(".") if r != "."];[os.makedirs(os.path.join(sys.argv[1],i)) for i in dirs]' ~/new_destination
FYI:
Here is a solution in php that:
Create a file like syncDirs.php
with this content:
<?php
foreach (new DirectoryIterator($argv[1]) as $f) {
if($f->isDot() || !$f->isDir()) continue;
mkdir($argv[2].'/'.$f->getFilename(), $f->getPerms());
chown($argv[2].'/'.$f->getFilename(), $f->getOwner());
chgrp($argv[2].'/'.$f->getFilename(), $f->getGroup());
}
Run it as user that has enough rights:
sudo php syncDirs.php /var/source /var/destination
This solves even the problem with whitespaces:
In the original/source dir:
find . -type d -exec echo "'{}'" \; > dirs2.txt
then recreate it in the newly created dir:
mkdir -p <../<SOURCEDIR>/dirs2.txt
find source/ -type f | rsync -a --exclude-from - source/ target/
Copy dir only with associated permission and ownership
Another approach is use the tree
which is pretty handy and navigating directory trees based on its strong options. There are options for directory only, exclude empty directories, exclude names with pattern, include only names with pattern, etc. Check out man tree
Advantage: you can edit or review the list, or if you do a lot of scripting and create a batch of empty directories frequently
Approach: create a list of directories using tree
, use that list as an arguments input to mkdir
tree -dfi --noreport > some_dir_file.txt
-dfi
lists only directories, prints full path for each name, makes tree not print the indentation lines,
--noreport
Omits printing of the file and directory report at the end of the tree listing, just to make the output file not contain any fluff
Then go to the destination where you want the empty directories and execute
xargs mkdir < some_dir_file.txt
cd /path/to/directories &&
find . -type d -exec mkdir -p -- /path/to/backup/{} \;
Here is a simple solution using rsync:
rsync -av -f"+ */" -f"- *" "$source" "$target"
If you can get access from a Windows machine, you can use xcopy with /T and /E to copy just the folder structure (the /E includes empty folders)
[EDIT!]
This one uses rsync to recreate the directory structure but without the files. http://psung.blogspot.com/2008/05/copying-directory-trees-with-rsync.html
Might actually be better :)
The following solution worked well for me in various environments:
sourceDir="some/directory"
targetDir="any/other/directory"
find "$sourceDir" -type d | sed -e "s?$sourceDir?$targetDir?" | xargs mkdir -p
I dunno if you are looking for a solution on Linux. If so, you can try this:
$ mkdir destdir
$ cd sourcedir
$ find . -type d | cpio -pdvm destdir
Source: Stackoverflow.com