ASP NET MVC Razor How to render a Razor Partial View s HTML inside the controller action

Question

How to generate a HTML of a given partial view on ASP NET view engine is known   But if this functionality is used on razor partial view it does not work  as exception says the partial view does not derive from  UserControl    How to fix the rendering to support razor partial view   I need this because I generate emails form this partial views      UPDATE   Code that fails   mcl    public string RenderPartialToString string controlName  object viewData                ViewPage viewPage   new ViewPage     ViewContext   new ViewContext              viewPage Url   this GetUrlHelper             string fullControlName      Views Email     controlName     ascx            viewPage ViewData   new ViewDataDictionary viewData           viewPage Controls Add viewPage LoadControl fullControlName             StringBuilder sb   new StringBuilder            using  StringWriter sw   new StringWriter sb                         using  HtmlTextWriter tw   new HtmlTextWriter sw                                 viewPage RenderControl tw                                   return sb ToString

User · Answer

great code  little hint  if you sometimes have to bypass more data and not only the viewmodel       if  model is ViewDataDictionary          controller ViewData   model as ViewDataDictionary     else        controller ViewData Model   model

User · Answer

You could also use the RenderView Controller extension from here  source   and use it like this   public ActionResult Do     var html   this RenderView  index   theModel           it works for razor and web-forms viewengines

User · Answer

Although adequate answers have already been given  I d like to propose a less verbose solution  that can be used without the helper methods available in an MVC controller class   Using a third party library called  RazorEngine  you can use  Net file IO to get the contents of the razor file and call  string html   Razor Parse razorViewContentString  modelObject     Get the third party library here

User · Answer

I saw that someone was wondering how to do it for another controller   In my case I had all of my email templates in the Views Email folder  but you could modify this to pass in the controller in which you have views associated for   public static string RenderViewToString Controller controller  string viewName  object model                var oldController   controller RouteData Values  controller   ToString             if  controller GetType      typeof EmailController               controller RouteData Values  controller      Email            var oldModel   controller ViewData Model          controller ViewData Model   model          try                       using  var sw   new StringWriter                                  var viewResult   ViewEngines Engines FindView controller ControllerContext  viewName                                                                             null                    var viewContext   new ViewContext controller ControllerContext  viewResult View  controller ViewData  controller TempData  sw                   viewResult View Render viewContext  sw                      Cleanup                 controller ViewData Model   oldModel                  controller RouteData Values  controller     oldController                   return sw GetStringBuilder   ToString                                    catch  Exception ex                        Elmah ErrorSignal FromCurrentContext   Raise ex                throw ex                    Essentially what this does is take a controller  such as AccountController and modify it to think it s an EmailController so that the code will look in the Views Email folder  It s necessary to do this because the FindView method doesn t take a straight up path as a parameter  it wants a ControllerContext    Once done rendering the string  it returns the AccountController back to its initial state to be used by the Response object

User · Answer

Borrowing  jgauffin answer as an HtmlHelper extension     public static class HtmlHelperExtensions       public static MvcHtmlString RenderPartialViewToString          this HtmlHelper html           ControllerContext controllerContext           ViewDataDictionary viewData          TempDataDictionary tempData          string viewName           object model                viewData Model   model          string result   String Empty           using  StringWriter sw   new StringWriter                          ViewEngineResult viewResult   ViewEngines Engines FindPartialView controllerContext  viewName               ViewContext viewContext   new ViewContext controllerContext  viewResult View  viewData  tempData  sw               viewResult View Render viewContext  sw                result   sw GetStringBuilder   ToString                       return MvcHtmlString Create result             Usage in a razor view   Html RenderPartialViewToString ViewContext  ViewData  TempData   Search   Model

User · Answer

Html Partial  nameOfPartial   Model    Update  protected string RenderPartialViewToString string viewName  object model        if  string IsNullOrEmpty viewName           viewName   ControllerContext RouteData GetRequiredString  action         ViewData Model   model       using  StringWriter sw   new StringWriter              ViewEngineResult viewResult   ViewEngines Engines FindPartialView ControllerContext  viewName           ViewContext viewContext   new ViewContext ControllerContext  viewResult View  ViewData  TempData  sw           viewResult View Render viewContext  sw            return sw GetStringBuilder   ToString

[c#] ASP.NET MVC Razor: How to render a Razor Partial View's HTML inside the controller action

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