Python regex to match dates

Question

What regular expression in Python do I use to match dates like this   11 12 98

User · Answer

Well  from my understanding  simply for matching this format in a given string  I prefer this regular expression   pattern   0-9        to match the format in a more strict way  the following works   pattern      0-9  2    2  0-9  2     Personally  I cannot agree with unutbu s answer since sometimes we use regular expression for  finding  and  extract   not only  validating

User · Answer

Sometimes we need to get the date from a string  One example with grouping   record    1518-09-06 00 57 some-alphanumeric-charecter  pattern date time     0-9  4 - 0-9  2 - 0-9  2   0-9  2   0-9  2      match   re match pattern date time  record  if match is not None    group   match group     date   group 0    print date     outputs 1518-09-06 00 57

User · Answer

I use something like this  gt  gt  gt  import datetime  gt  gt  gt  regex   datetime datetime strptime  gt  gt  gt   gt  gt  gt    TEST  gt  gt  gt  assert regex  2020-08-03     Y- m- d    gt  gt  gt    gt  gt  gt  assert regex  2020-08     Y- m- d   ValueError  time data  2020-08  does not match format   Y- m- d    gt  gt  gt  assert regex  08 03 20     m  d  y    gt  gt  gt    gt  gt  gt  assert regex  08-03-2020     m  d  y   ValueError  time data  08-03-2020  does not match format   m  d  y

User · Answer

I built my solution on top of  aditya Prakash appraoch    print re search     1-9  0 1-9  1 0-9  2 0-9  3 0-1      -     1-9  0 1-9  1 0-2      -     0-9  0-9  19 0-9  0-9  20 0-9  0-9       0-9  0-9  19 0-9  0-9  20 0-9  0-9      -     1-9  0 1-9  1 0-2      -     1-9  0 1-9  1 0-9  2 0-9  3 0-1      01 01 2018      The first part     1-9  0 1-9  1 0-9  2 0-9  3 0-1      -     1-9  0 1-9  1 0-2      -     0-9  0-9  19 0-9  0-9  20 0-9  0-9     can handle the following formats    01 10 2019 1 1 2019 1 1 19 12 03 2020 01 05 1950   The second part     0-9  0-9  19 0-9  0-9  20 0-9  0-9      -     1-9  0 1-9  1 0-2      -     1-9  0 1-9  1 0-9  2 0-9  3 0-1     can basically do the same  but in inverse order  where the year comes first  followed by month  and then day    2020 02 12   As delimiters it allows       -  As years it allows everything from 1900-2099  also giving only two numbers is fine   If you have suggestions for improvement please let me know in the comments  so I can update the answer

User · Answer

As the question title asks for a regex that finds many dates  I would like to propose a new solution  although there are many solutions already   In order to find all dates of a string that are in this millennium  2000 - 2999   for me it worked the following   dates   re findall    1-9  1 0-9  2 0-9  3 0-1  0 0-9     -      1-9  1 0-2  0 0-9     -     20 0-9  0-9    dates ele   dates       join dates i   for i in range len dates      This regex is able to find multiple dates in the same string  like bla Bla 8 05 2020  n BLAH bla15 05-2020 blaa   As one could observe  instead of   the date can have   or -  not necessary at the same time   Some explaining  More specifically it can find dates of format day   moth year  Day is an one digit integer or a zero followed by one digit integer or 1 or 2 followed by an one digit integer or a 3 followed by 0 or 1  Month is an one digit integer or a zero followed by one digit integer or 1 followed by 0  1  or 2  Year is the number 20 followed by any number between 00 and 99   Useful notes  One can add more date splitting symbols by adding   symbol at the end of both    -      For example for adding -- one would do    -    --   To have years outside of this millennium one has to modify  20 0-9  0-9   to   0-9  0-9  0-9  0-9

User · Answer

I find the below RE working fine for Date in the following format     14-11-2017 14 11 2017 14 11 2017   It can accept year from 2000-2099  Please do not forget to add   at the end if not it accept 14-11-201 or 20177  date  13-11-2017   x re search     1-9   1 0-9   2 0-9  3 0-1     -   1-9   1 0-2     -  20 0-9  0-9    date   x group     output    13-11-2017

User · Answer

Using this regular expression you can validate different kinds of Date Time samples  just a little change is needed     d d d d  0  1-9  1 0-2    0  1-9   12  0-9  3 01    00  0-9  1 0-9  2 0-3     0-9   0-5  0-9     0-9   0-5  0-9    -- validate this  2018 7 12 13 00 00  for your format you cad change it to     0  1-9   12  0-9  3 01    0  1-9  1 0-2    d d  --  validates this  11 12 98

User · Answer

Instead of using regex  it is generally better to parse the string as a datetime datetime object   In  140   datetime datetime strptime  11 12 98    m  d  y   Out 140   datetime datetime 1998  11  12  0  0   In  141   datetime datetime strptime  11 12 98    d  m  y   Out 141   datetime datetime 1998  12  11  0  0    You could then access the day  month  and year  and hour  minutes  and seconds  as attributes of the datetime datetime object   In  143   date year Out 143   1998  In  144   date month Out 144   11  In  145   date day Out 145   12   To test if a sequence of digits separated by forward-slashes represents a valid date  you could use a try  except block  Invalid dates will raise a ValueError   In  159   try                datetime datetime strptime  99 99 99    m  d  y             except ValueError as err                print err                                time data  99 99 99  does not match format   m  d  y      If you need to search a longer string for a date   you could use regex to search for digits separated by forward-slashes   In  146   import re In  152   match   re search r   d   d   d     The date is 11 12 98    In  153   match group 1  Out 153    11 12 98    Of course  invalid dates will also match   In  154   match   re search r   d   d   d     The date is 99 99 99    In  155   match group 1  Out 155    99 99 99    To check that match group 1  returns a valid date string  you could then parsing it using datetime datetime strptime as shown above

[python] Python regex to match dates

Examples related to python

Examples related to regex

Examples related to date