[c++] What is a lambda expression in C++11?

The lambda's in c++ are treated as "on the go available function". yes its literally on the go, you define it; use it; and as the parent function scope finishes the lambda function is gone.

c++ introduced it in c++ 11 and everyone started using it like at every possible place. the example and what is lambda can be find here https://en.cppreference.com/w/cpp/language/lambda

i will describe which is not there but essential to know for every c++ programmer

Lambda is not meant to use everywhere and every function cannot be replaced with lambda. It's also not the fastest one compare to normal function. because it has some overhead which need to be handled by lambda.

it will surely help in reducing number of lines in some cases. it can be basically used for the section of code, which is getting called in same function one or more time and that piece of code is not needed anywhere else so that you can create standalone function for it.

Below is the basic example of lambda and what happens in background.

User code:

int main()
{
  // Lambda & auto
  int member=10;
  auto endGame = [=](int a, int b){ return a+b+member;};

  endGame(4,5);

  return 0;

}

How compile expands it:

int main()
{
  int member = 10;

  class __lambda_6_18
  {
    int member;
    public: 
    inline /*constexpr */ int operator()(int a, int b) const
    {
      return a + b + member;
    }

    public: __lambda_6_18(int _member)
    : member{_member}
    {}

  };

  __lambda_6_18 endGame = __lambda_6_18{member};
  endGame.operator()(4, 5);

  return 0;
}

so as you can see, what kind of overhead it adds when you use it. so its not good idea to use them everywhere. it can be used at places where they are applicable.

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