[c++] Passing capturing lambda as function pointer

Shafik Yaghmour's answer correctly explains why the lambda cannot be passed as a function pointer if it has a capture. I'd like to show two simple fixes for the problem.

  1. Use std::function instead of raw function pointers.

    This is a very clean solution. Note however that it includes some additional overhead for the type erasure (probably a virtual function call).

    #include <functional>
    #include <utility>
    
    struct Decide
    {
      using DecisionFn = std::function<bool()>;
      Decide(DecisionFn dec) : dec_ {std::move(dec)} {}
      DecisionFn dec_;
    };
    
    int
    main()
    {
      int x = 5;
      Decide greaterThanThree { [x](){ return x > 3; } };
    }
    
  2. Use a lambda expression that doesn't capture anything.

    Since your predicate is really just a boolean constant, the following would quickly work around the current issue. See this answer for a good explanation why and how this is working.

    // Your 'Decide' class as in your post.
    
    int
    main()
    {
      int x = 5;
      Decide greaterThanThree {
        (x > 3) ? [](){ return true; } : [](){ return false; }
      };
    }
    

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