Convert string into Date type on Python

Question

I have this string    2012-02-10     year-month-day    and I need it to be as date type for me to use the date function isoweekday     Does anyone know how I can convert this string into a date

User · Answer

Use datetime datetime strptime    gt  gt  gt  import datetime  gt  gt  gt  date   datetime datetime strptime  2012-02-10     Y- m- d    gt  gt  gt  date isoweekday   5

User · Answer

You can do that with datetime strptime    Example    gt  gt  gt  from datetime import datetime  gt  gt  gt  datetime strptime  2012-02-10      Y- m- d   datetime datetime 2012  2  10  0  0   gt  gt  gt    isoweekday   5   You can find the table with all the strptime directive here     To increment by 2 days if  isweekday      6  you can use timedelta      gt  gt  gt  import datetime  gt  gt  gt  date   datetime datetime strptime  2012-02-11      Y- m- d    gt  gt  gt  if date isoweekday      6          date    datetime timedelta days 2        gt  gt  gt  date datetime datetime 2012  2  13  0  0   gt  gt  gt  date strftime   Y- m- d       if you want a string again  2012-02-13

User · Answer

While it seems the question was answered per the OP s request  none of the answers give a good way to get a datetime date object instead of a datetime datetime  So for those searching and finding this thread   datetime date has no  strptime method  use the one on datetime datetime instead and then call  date   on it to receive the datetime date object    Like so    gt  gt  gt  from datetime import datetime  gt  gt  gt  datetime strptime  2014-12-04     Y- m- d   date   datetime date 2014  12  4

User · Answer

from datetime import datetime  a   datetime strptime f    Y- m- d

User · Answer

gt  gt  gt  from datetime import datetime  gt  gt  gt  year  month  day   map int  my date split  -     gt  gt  gt  date object   datetime year  month  day

[python] Convert string into Date type on Python

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