How do I return a proper success error message for JQuery ajax using PHP

Question

I keep getting the error alert  There is nothing wrong with the MYSQL part  the query gets executed and I can see the email addresses in the db   The client side    lt script type  text javascript  gt      function            form subsribe form   submit function           var email       email   val             ajax           url   subscribe php           type   POST           data   email  email           dataType   json           success  function               alert  Thank you for subscribing                        error  function               alert  There was an error  Try again please                               return false                 lt  script gt    The server side    lt  php   user  username    password  password    database  database    mysql connect localhost  user  password   mysql select db  database  or die   Unable to select database      senderEmail   isset    POST  email       preg replace         -    a-zA-Z0-9           POST  email            if  senderEmail             query    INSERT INTO participants col1   col2  VALUES  CURDATE       senderEmail       mysql query  query   mysql close      response array  status      success        echo json encode  response array     gt

User · Answer

Just so you know  you can use this for debugging  It helped me a lot  and still does  error function x e        if  x status  0            alert  You are offline   n Please Check Your Network           else if x status  404            alert  Requested URL not found           else if x status  500            alert  Internel Server Error           else if e   parsererror             alert  Error  nParsing JSON Request failed           else if e   timeout            alert  Request Time out           else           alert  Unknow Error  n  x responseText

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Some people recommend using HTTP status codes  but I rather despise that practice  e g  If you re doing a search engine and the provided keywords have no results  the suggestion would be to return a 404 error   However  I consider that wrong  HTTP status codes apply to the actual browser lt - server connection  Everything about the connect went perfectly  The browser made a request  the server invoked your handler script  The script returned  no rows   Nothing in that signifies  404 page not found  - the page WAS found   Instead  I favor divorcing the HTTP layer from the status of your server-side operations  Instead of simply returning some text in a json string  I always return a JSON data structure which encapsulates request status and request results   e g  in PHP you d have   results   array      error    gt  false      error msg    gt   Everything A-OK       data    gt  array     results of request here         echo json encode  results     Then in your client-side code you d have  if   data error           got data  do something with it       else          invoke error handler

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you may also want to check for cross site scripting issues   if your html pages comes from a different domain port combi then your rest service  your browser may block the call   Typically  right mouse- inspect on your html page  Then look in the error console for errors like   Access to XMLHttpRequest at      8080  from origin      8383  has been blocked by    CORS policy  No  Access-Control-Allow-Origin  header is present on the requested    resource

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adding to the top answer  here is some sample code from PHP and Jquery       button   click function         ajax               type   POST               url   handler php               data  dataString                   success  function data                       if data status     success                         alert  Thank you for subscribing                               title   html                              message   html data message                       hide   fadeIn 1000  function                                 message   append                                 delay 1000  fadeOut  fast                            setTimeout function                           window location href    myhome php                          2500                                             else if data status     error                          alert  Error on query                                                                          return false                PHP - send custom message   status        response array  status      success      match error string in jquery if else          response array  message      RFQ Sent         add custom message         header  Content-type  application json        echo json encode  response array

User · Answer

I had the same issue  My problem was that my header type wasn t set properly   I just added this before my json echo  header  Content-type  application json

User · Answer

In order to build an AJAX webservice  you need TWO files      A calling Javascript that sends data as POST  could be as GET  using JQuery AJAX A PHP webservice that returns a JSON object  this is convenient to return arrays or large amount of data    So  first you call your webservice using this JQuery syntax  in the JavaScript file      ajax        url    mywebservice php        type    POST        data    records to export     selected ids     On fait passer nos variables  exactement comme en GET  au script more com php      dataType    json        success  function  data              alert  The file is   data fichierZIP                error  function data                console log data             var responseText JSON parse data responseText             alert  Error s  while building the ZIP file  n  responseText messages                Your PHP file  mywebservice php  as written in the AJAX call  should include something like this in its end  to return a correct Success or Error status    lt  php                 I am processing the data that the calling Javascript just ordered  it is in the   POST   In this example  details not shown   I built a ZIP file and have its filename in variable   filename         errors is a string that may contain an error message while preparing the ZIP file       In the end  I check if there has been an error  and if so  I return an error object                if   errors                 if there is no error  the header is normal  and you return your JSON object to the calling JavaScript         header  Content-Type  application json  charset UTF-8             result array             result  ZIPFILENAME     basename  filename            print json encode  result         else             if there is an error  you should return a special header  followed by another JSON object         header  HTTP 1 1 500 Internal Server Booboo            header  Content-Type  application json  charset UTF-8             result array             result  messages      errors            feel free to add other information like  result  errorcode           die json encode  result            gt

User · Answer

Server side   if  mysql query  query                  else       ajaxError         Client side   error  function         alert  There was an error  Try again please        success  function        alert  Thank you for subscribing

User · Answer

You need to provide the right content type if you re using JSON dataType  Before echo-ing the json  put the correct header    lt  php         header  Content-type  application json        echo json encode  response array     gt    Additional fix  you should check whether the query succeed or not   if mysql query  query         response array  status      success      else        response array  status      error         On the client side   success  function data        if data status     success            alert  Thank you for subscribing          else if data status     error            alert  Error on query                Hope it helps

[php] How do I return a proper success/error message for JQuery .ajax() using PHP?

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