How to program a delay in Swift 3

Question

In earlier versions of Swift  one could create a delay with the following code   let time   dispatch time dispatch time t DISPATCH TIME NOW   4   Int64 NSEC PER SEC   dispatch after time  dispatch get main queue            put your code which should be executed with a delay here     But now  in Swift 3  Xcode automatically changes 6 different things but then the following error appears   Cannot convert DispatchTime now to expected value dispatch time t aka UInt64    How can one create a delay before running a sequence of code in Swift 3

User · Answer

Runs function after x seconds  public static func runThisAfterDelay seconds  Double  after   escaping    - gt  Void        runThisAfterDelay seconds  seconds  queue  DispatchQueue main  after  after     public static func runThisAfterDelay seconds  Double  queue  DispatchQueue  after   escaping    - gt  Void        let time   DispatchTime now     Double Int64 seconds   Double NSEC PER SEC      Double NSEC PER SEC      queue asyncAfter deadline  time  execute  after        Use -  runThisAfterDelay seconds  x       write your code here

User · Answer

Try the below code for delay    MARK  First Way  func delayForWork         delay 3 0            print  delay for 3 0 second            delayForWork          MARK  Second Way  DispatchQueue main asyncAfter deadline   now     0 5           your code here delayed by 0 5 seconds

User · Answer

One way is to use DispatchQueue main asyncAfter as a lot of people have answered   Another way is to use perform   with afterDelay    More details here  perform  selector delayedFunc   with  nil  afterDelay  3    IBAction func delayedFunc            implement code

User · Answer

I like one-line notation for GCD  it s more elegant       DispatchQueue main asyncAfter deadline   now     42 0               do stuff 42 seconds later         Also  in iOS 10 we have new Timer methods  e g  block initializer    so delayed action may be canceled       let timer   Timer scheduledTimer withTimeInterval  42 0  repeats  false     timer  in            do stuff 42 seconds later         Btw  keep in mind  by default  timer is added to the default run loop mode  It means timer may be frozen when the user is interacting with the UI of your app  for example  when scrolling a UIScrollView  You can solve this issue by adding the timer to the specific run loop mode   RunLoop current add timer  forMode   common    At this blog post you can find more details

User · Answer

After a lot of research  I finally figured this one out   DispatchQueue main asyncAfter deadline   now     2 0       Change  2 0  to the desired number of seconds        Code you want to be delayed     This creates the desired  wait  effect in Swift 3 and Swift 4   Inspired by a part of this answer

User · Answer

Try the following function implemented in Swift 3 0 and above  func delayWithSeconds   seconds  Double  completion   escaping    - gt            DispatchQueue main asyncAfter deadline   now     seconds             completion             Usage  delayWithSeconds 1         Do something

[ios] How to program a delay in Swift 3

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