how to open an URL in Swift3

Question

openURL has been deprecated in Swift3   Can anyone provide some examples of how the replacement openURL options completionHandler  works when trying to open an url

User · Answer

Swift 3 version  import UIKit  protocol PhoneCalling       func call phoneNumber  String     extension PhoneCalling       func call phoneNumber  String            let cleanNumber   phoneNumber replacingOccurrences of       with      replacingOccurrences of   -   with              guard let number   URL string   telprompt       cleanNumber  else   return            UIApplication shared open number  options       completionHandler  nil

User · Answer

I m using macOS Sierra  v10 12 1  Xcode v8 1 Swift 3 0 1 and here s what worked for me in ViewController swift          ViewController swift     UIWebViewExample        Created by Scott Maretick on 1 2 17      Copyright    2017 Scott Maretick  All rights reserved      import UIKit import WebKit  class ViewController  UIViewController          added this code      IBOutlet weak var webView  UIWebView       override func viewDidLoad             super viewDidLoad              Your webView code goes here         let url   URL string   https   www google com           if UIApplication shared canOpenURL url                 UIApplication shared open url   options       completionHandler  nil                If you want handle the completion block than             UIApplication shared open url   options       completionHandler     success  in                 print  Open url     success                                       override func didReceiveMemoryWarning             super didReceiveMemoryWarning              Dispose of any resources that can be recreated

User · Answer

If you want to open inside the app itself instead of leaving the app you can import SafariServices and work it out   import UIKit import SafariServices  let url   URL string   https   www google com   let vc   SFSafariViewController url  url   present vc  animated  true  completion  nil

User · Answer

Above answer is correct but if you want to check you canOpenUrl or not try like this   let url   URL string   http   www facebook com    if UIApplication shared canOpenURL url        UIApplication shared open url  options       completionHandler  nil        If you want handle the completion block than      UIApplication shared open url  options       completionHandler     success  in          print  Open url     success               Note  If you do not want to handle completion you can also write like this   UIApplication shared open url  options         No need to write completionHandler as it contains default value nil  check apple documentation for more detail

User · Answer

import UIKit  import SafariServices   let url   URL string   https   sprotechs com   let vc   SFSafariViewController url  url    present vc  animated  true  completion  nil

User · Answer

All you need is   guard let url   URL string   http   www google com   else     return   be safe    if  available iOS 10 0           UIApplication shared open url  options       completionHandler  nil    else       UIApplication shared openURL url

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