iOS detect if user is on an iPad

Question

I have an app that runs on the iPhone and iPod Touch  it can run on the Retina iPad and everything but there needs to be one adjustment  I need to detect if the current device is an iPad  What code can I use to detect if the user is using an iPad in my UIViewController and then change something accordingly

User · Answer

You can also use this   define IPAD UI USER INTERFACE IDIOM      UIUserInterfaceIdiomPad     if  IPAD          iPad   else         iPhone   iPod Touch

User · Answer

if UI USER INTERFACE IDIOM       UIUserInterfaceIdiom pad                 print  This is iPad     else if  UI USER INTERFACE IDIOM       UIUserInterfaceIdiom phone                 print  This is iPhone

User · Answer

There are quite a few ways to check if a device is an iPad  This is my favorite way to check whether the device is in fact an iPad   if   UI USER INTERFACE IDIOM      UIUserInterfaceIdiomPad         return YES     Device is iPad        The way I use it   define IDIOM    UI USER INTERFACE IDIOM    define IPAD     UIUserInterfaceIdiomPad  if   IDIOM    IPAD            do something specifically for iPad       else          do something specifically for iPhone or iPod touch            Other Examples  if     NSString   UIDevice currentDevice  model hasPrefix   iPad           return YES     Device is iPad        define IPAD      UI USER INTERFACE IDIOM      UIUserInterfaceIdiomPad  if   IPAD         return YES    For a Swift solution  see this answer  https   stackoverflow com a 27517536 2057171

User · Answer

You can check the rangeOfString to see of the word iPad exists like this   NSString  deviceModel    NSString   UIDevice currentDevice  model   if   deviceModel rangeOfString   iPad   location    NSNotFound     NSLog   I am an iPad      else   NSLog   I am not an iPad

User · Answer

For the latest versions of iOS  simply add UITraitCollection   extension UITraitCollection        var isIpad  Bool           return horizontalSizeClass     regular  amp  amp  verticalSizeClass     regular           and then within UIViewController just check   if traitCollection isIpad

User · Answer

Yet another Swifty way     MARK  -  Device Check let iPad   UIUserInterfaceIdiom Pad let iPhone   UIUserInterfaceIdiom Phone  available iOS 9 0        AppleTV check is iOS9     let TV   UIUserInterfaceIdiom TV  extension UIDevice       static var type  UIUserInterfaceIdiom            return UIDevice currentDevice   userInterfaceIdiom       Usage   if UIDevice type    iPhone         it s an iPhone     if UIDevice type    iPad         it s an iPad     if UIDevice type    TV         it s an  TV

User · Answer

Why so complicated  This is how I do it     Swift 4   var iPad   Bool       return UIDevice current model contains  iPad       This way you can just say if iPad

User · Answer

I found that some solution didn t work for me in the Simulator within Xcode  Instead  this works   ObjC  NSString  deviceModel    NSString   UIDevice currentDevice  model   if    deviceModel substringWithRange NSMakeRange 0  4   isEqualToString   iPad          DebugLog   iPad      else       DebugLog   iPhone or iPod Touch        Swift  if UIDevice current model hasPrefix  iPad         print  iPad     else       print  iPhone or iPod Touch       Also in the  Other Examples  in Xcode the device model comes back as  iPad Simulator  so the above tweak should sort that out

User · Answer

Be Careful  If your app is targeting iPhone device only  iPad running with iphone compatible mode will return false for below statement    define IPAD     UI USER INTERFACE IDIOM      UIUserInterfaceIdiomPad   The right way to detect physical iPad device is    define IS IPAD DEVICE         NSString    UIDevice currentDevice  model hasPrefix   iPad

User · Answer

In Swift 4 2 and Xcode 10  if UIDevice   userInterfaceIdiom     phone         This is iPhone   else if UIDevice   userInterfaceIdiom     pad          This is iPad   else if UIDevice   userInterfaceIdiom     tv         This is Apple TV     If you want to detect specific device   let screenHeight   UIScreen main bounds size height if UIDevice   userInterfaceIdiom     phone       if  screenHeight  gt   667            print  iPhone 6 and later         else if  screenHeight    568            print  SE  5C  5S         else if screenHeight lt  480           print  4S           else if UIDevice   userInterfaceIdiom     pad          This is iPad

User · Answer

UI USER INTERFACE IDIOM   only returns iPad if the app is for iPad or Universal  If its an iPhone app running on an iPad then it won t  So you should instead check the model

User · Answer

Many ways to do that in Swift   We check the model below  we can only do a case sensitive search here    class func isUserUsingAnIpad   - gt  Bool       let deviceModel   UIDevice currentDevice   model     let result  Bool   NSString string  deviceModel  containsString  iPad       return result     We check the model below  we can do a case sensitive insensitive search here        class func isUserUsingAnIpad   - gt  Bool           let deviceModel   UIDevice currentDevice   model         let deviceModelNumberOfCharacters  Int   count deviceModel          if deviceModel rangeOfString  iPad                                        options  NSStringCompareOptions LiteralSearch                                       range  Range lt String Index gt  start  deviceModel startIndex                                                                  end  advance deviceModel startIndex  deviceModelNumberOfCharacters                                         locale  nil     nil               return true           else               return false                  UIDevice currentDevice   userInterfaceIdiom below only returns iPad if the app is for iPad or Universal  If it is an iPhone app being ran on an iPad then it won t  So you should instead check the model         class func isUserUsingAnIpad   - gt  Bool           if UIDevice currentDevice   userInterfaceIdiom    UIUserInterfaceIdiom Pad               return true           else               return false                  This snippet below does not compile if the class does not inherit of an UIViewController  otherwise it works just fine  Regardless UI USER INTERFACE IDIOM   only returns iPad if the app is for iPad or Universal  If it is an iPhone app being ran on an iPad then it won t  So you should instead check the model     class func isUserUsingAnIpad   - gt  Bool       if  UI USER INTERFACE IDIOM      UIUserInterfaceIdiom Pad            return true       else           return false

User · Answer

In swift 3 0       if UIDevice current userInterfaceIdiom     pad             pad       else if UIDevice current userInterfaceIdiom     phone             phone       else if UIDevice current userInterfaceIdiom     tv             tv       else if UIDevice current userInterfaceIdiom     carPlay             CarDisplay       else             unspecified

User · Answer

I don t think any of these answers meet my need  unless I am fundamentally misunderstanding something  I have an app  originally an iPad app  that I want to run both on an iPad and on the Mac  under Catalyst  I m using the plist option to scale the Mac interface to match the iPad  but would like to migrate to AppKit if that is reasonable  When running on a Mac  I believe that all of the aforementioned approaches tell me that I m on an iPad  The Catalyst fake-out is pretty thorough  For most concerns I indeed understand that the code should pretend it s on an iPad when thus running on a Mac  One exception is that the rolling picker is not available on the Mac under Catalyst  but is on the iPad  I want to figure out whether to create a UIPickerView or to do something different  at run time  Run-time selection is crucial because I want to use a single binary to run both on the iPad and Mac in the long term  while making the best use of the supported UI standards on each  The APIs give potentially misleading results to the casual pre-Catalyst reader  For example   UIDevice currentDevice  model returns   quot iPad quot  when running under Catalyst on a Mac  The user interface idiom APIs sustain the same illusion  I found that you really need to look deeper  I start with this information  NSString  const deviceModel    UIDevice currentDevice  model  NSProcessInfo  const processInfo     NSProcessInfo alloc  init   const bool isIosAppOnMac   processInfo iOSAppOnMac      Note  this will be  quot no quot  under Catalyst const bool isCatalystApp   processInfo macCatalystApp   Then you can combine these queries with expressions like  deviceModel hasPrefix    quot iPad quot   to sort out the kinds of subtleties I m facing  For my case  I explicitly want to avoid making a UIPickerView if the indicated isCatalystApp is true  independent of  quot misleading quot  information about the interface idiom  or the illusions sustained by isIosAppOnMac and deviceModel  Now I m curious what happens if I move the Mac app to run over on my iPad sidecar

User · Answer

In Swift you can use the following equalities to determine the kind of device on Universal apps   UIDevice current userInterfaceIdiom     phone    or UIDevice current userInterfaceIdiom     pad   Usage would then be something like   if UIDevice current userInterfaceIdiom     pad          Available Idioms -  pad   phone   tv   carPlay   unspecified        Implement your logic here

User · Answer

This is part of UIDevice as of iOS 3 2  e g     UIDevice currentDevice  userInterfaceIdiom    UIUserInterfaceIdiomPad

User · Answer

Many Answers are good but I use like this in swift 4   Create Constant  struct App       static let isRunningOnIpad   UIDevice current userInterfaceIdiom     pad   true   false    Use like this  if App isRunningOnIpad       return load from   main  identifier  identifier    else       return load from   ipad  identifier  identifier       Edit   As Suggested C  ur simply create an extension on UIDevice  extension UIDevice       static let isRunningOnIpad   UIDevice current userInterfaceIdiom     pad   true   false

[ios] iOS detect if user is on an iPad

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