You can use just:
"{0:b}".format(n)
In my opinion this is the easiest way!
('0' * 7 + bin(6)[2:])[-8:]
or
right_side = bin(6)[2:]
'0' * ( 8 - len( right_side )) + right_side
Going Old School always works
def intoBinary(number):
binarynumber=""
if (number!=0):
while (number>=1):
if (number %2==0):
binarynumber=binarynumber+"0"
number=number/2
else:
binarynumber=binarynumber+"1"
number=(number-1)/2
else:
binarynumber="0"
return "".join(reversed(binarynumber))
Just use the format function
format(6, "08b")
The general form is
format(<the_integer>, "<0><width_of_string><format_specifier>")
.. or if you're not sure it should always be 8 digits, you can pass it as a parameter:
>>> '%0*d' % (8, int(bin(6)[2:]))
'00000110'
Assuming you want to parse the number of digits used to represent from a variable which is not always constant, a good way will be to use numpy.binary.
could be useful when you apply binary to power sets
import numpy as np
np.binary_repr(6, width=8)
The best way is to specify the format.
format(a, 'b')
returns the binary value of a in string format.
To convert a binary string back to integer, use int() function.
int('110', 2)
returns integer value of binary string.
def int_to_bin(num, fill):
bin_result = ''
def int_to_binary(number):
nonlocal bin_result
if number > 1:
int_to_binary(number // 2)
bin_result = bin_result + str(number % 2)
int_to_binary(num)
return bin_result.zfill(fill)
A bit twiddling method...
>>> bin8 = lambda x : ''.join(reversed( [str((x >> i) & 1) for i in range(8)] ) )
>>> bin8(6)
'00000110'
>>> bin8(-3)
'11111101'
numpy.binary_repr(num, width=None)
has a magic width argumentRelevant examples from the documentation linked above:
>>> np.binary_repr(3, width=4) '0011'
The two’s complement is returned when the input number is negative and width is specified:
>>> np.binary_repr(-3, width=5) '11101'
eumiro's answer is better, however I'm just posting this for variety:
>>> "%08d" % int(bin(6)[2:])
00000110
even an easier way
my_num = 6
print(f'{my_num:b}')
Just another idea:
>>> bin(6)[2:].zfill(8)
'00000110'
Shorter way via string interpolation (Python 3.6+):
>>> f'{6:08b}'
'00000110'
Source: Stackoverflow.com