PHP pass variable to include

Question

I m trying to pass a variable into an include file  My host changed PHP version and now whatever solution I try doesn t work   I think I ve tried every option I could find  I m sure it s the simplest thing   The variable needs to be set and evaluated from the calling first file  it s actually   SERVER  PHP SELF    and needs to return the path of that file  not the included second php    OPTION ONE  In the first file   global  variable   variable    apple   include  second php      In the second file   echo  variable    OPTION TWO  In the first file   function passvariable         variable    apple       return  variable    passvariable      OPTION THREE   variable    apple   include  myfile php var  variable      and I tried with http  and full site address too     variable     GET  var   echo  variable   None of these work for me  PHP version is 5 2 16   What am I missing   Thanks

User · Answer

I have the same problem here  you may use the  GLOBALS array    GLOBALS  variable      123   include   my php      It should also run doing this    myvar    123   include   my php           echo  GLOBALS  myvar      Have a nice day

User · Answer

You can execute all in  quot second php quot  adding variable with jQuery  lt div id  quot first quot  gt  lt  div gt    lt script gt     quot  first quot   load  quot second php a  lt  php echo  var  gt  quot    lt  scrpt gt

User · Answer

This worked for me  To wrap the contents of the second file into a function  as follows    firstFile php   lt  php     include  secondFile php         echoFunction  message      secondFile php   lt  php     function echoFunction  variable                echo  variable

User · Answer

Considering that an include statment in php at the most basic level takes the code from a file and pastes it into where you called it and the fact that the manual on include states the following       When a file is included  the code it contains inherits the variable scope of the line on which the include occurs  Any variables available at that line in the calling file will be available within the called file  from that point forward     These things make me think that there is a diffrent problem alltogether  Also Option number 3 will never work because you re not redirecting to second php you re just including it and option number 2 is just a weird work around  The most basic example of the include statment in php is    vars php  lt  php   color    green    fruit    apple      gt   test php  lt  php  echo  A  color  fruit      A  include  vars php    echo  A  color  fruit      A green apple    gt    Considering that option number one is the closest to this example  even though more complicated then it should be  and it s not working  its making me think that you  made a mistake in the include statement  the wrong path relative to the root or a similar issue

User · Answer

You can use the extract   function Drupal use it  in its theme   function   Here it is a render function with a  variables argument   function includeWithVariables  filePath   variables   array     print   true         output   NULL      if file exists  filePath               Extract the variables to a local namespace         extract  variables               Start output buffering         ob start                Include the template file         include  filePath              End buffering and return its contents          output   ob get clean              if   print            print  output            return  output          index php    includeWithVariables  header php   array  title    gt   Header Title         header php      lt h1 gt  lt  php echo  title    gt  lt  h1 gt

User · Answer

In regards to the OP s question  specifically  The variable needs to be set and evaluated from the calling first file  it s actually    SERVER  PHP SELF     and needs to return the path of that file  not the included second php      This will tell you what file included the file  Place this in the included file    includer   debug backtrace    echo  includer 0   file

User · Answer

I ve run into this issue where I had a file that sets variables based on the GET parameters   And that file could not updated because it worked correctly on another part of a large content management system   Yet I wanted to run that code via an include file without the parameters actually being in the URL string  The simple solution is you can set the GET variables in first file as you would any other variable    Instead of   include  myfile php var apple     It would be     GET  var      apple   include  myfile php

User · Answer

Do this    checksum    my value    header  Location  recordupdated php checksum  checksum

User · Answer

According to php docs  see   SERVER    SERVER  PHP SELF   is the  filename of the currently executing script    The INCLUDE statement  includes and evaluates the specified  file and  the code it contains inherits the variable scope of the line on which the include occurs   see INCLUDE    I believe   SERVER  PHP SELF   will return the filename of the 1st file  even when used by code in the  second php     I tested this with the following code and it works as expected   phpSelf is the name of the first file       In the first php file    get the value of   SERVER  PHP SELF   for the 1st file  phpSelf     SERVER  PHP SELF        include the second file    This slurps in the contents of second php include once  second php        execute  phpSelf     SERVER  PHP SELF    in the secod php file    echo the value of   SERVER  PHP SELF   of fist file  echo  phpSelf      This echos the name of the First php file

User · Answer

I found that the include parameter needs to be the entire file path  not a relative path or partial path for this to work

User · Answer

Option 3 is impossible - you d get the rendered output of the  php file  exactly as you would if you hit that url in your browser  If you got raw PHP code instead  as you d like   then ALL of your site s source code would be exposed  which is generally not a good thing   Option 2 doesn t make much sense - you d be hiding the variable in a function  and be subject to PHP s variable scope  You ld also have to have  var   passvariable   somewhere to get that  inside  variable to the  outside   and you re back to square one   option 1 is the most practical  include   will basically slurp in the specified file and execute it right there  as if the code in the file was literally part of the parent page  It does look like a global variable  which most people here frown on  but by PHP s parsing semantics  these two are identical    x    foo   include  bar php      and   x    foo      contents of bar php pasted here

User · Answer

I know this is an old question  but stumbled upon it now and saw nobody mentioned this  so writing it  The Option one if tweaked like this  it should also work  The Original  Option One In the first file  global  variable    variable    quot apple quot    include  second php      In the second file  echo  variable   TWEAK In the first file   variable    quot apple quot    include  second php     In the second file  global  variable  echo  variable

User · Answer

OPTION 1 worked for me  in PHP 7  and for sure it does in PHP 5 too  And the global scope declaration is not necessary for the included file for variables access  the included - or  required  - files are part of the script  only be sure you make the  include  AFTER the variable declaration  Maybe you have some misconfiguration with  variables global scope in your PHP ini    Try in first file      lt  php     myvariable  from first file     include     mysecondfile php       in same folder as first file LOLL     gt    mysecondfile php     lt  php    echo  this is my variable     myvariable      gt    It should work    if it doesn t just try to reinstall PHP

[php] PHP pass variable to include

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