I want to load the image like this:
void info(string channel)
{
//Something like that
channelPic.Image = Properties.Resources.+channel
}
Because I don't want to do
void info(string channel)
{
switch(channel)
{
case "chan1":
channelPic.Image = Properties.Resources.chan1;
break;
case "chan2":
channelPic.Image = Properties.Resources.chan2;
break;
}
}
Is something like this possible?
This question is related to
c#
image
resources
picturebox
You can do this using the ResourceManager
:
public bool info(string channel)
{
object o = Properties.Resources.ResourceManager.GetObject(channel);
if (o is Image)
{
channelPic.Image = o as Image;
return true;
}
return false;
}
Try this for WPF
StreamResourceInfo sri = Application.GetResourceStream(new Uri("pack://application:,,,/WpfGifImage001;Component/Images/Progess_Green.gif"));
picBox1.Image = System.Drawing.Image.FromStream(sri.Stream);
You can add an image resource in the project then (right click on the project and choose the Properties item) access that in this way:
this.picturebox.image = projectname.properties.resources.imagename;
this.toolStrip1 = new System.Windows.Forms.ToolStrip();
this.toolStrip1.Location = new System.Drawing.Point(0, 0);
this.toolStrip1.Name = "toolStrip1";
this.toolStrip1.Size = new System.Drawing.Size(444, 25);
this.toolStrip1.TabIndex = 0;
this.toolStrip1.Text = "toolStrip1";
object O = global::WindowsFormsApplication1.Properties.Resources.ResourceManager.GetObject("best_robust_ghost");
ToolStripButton btn = new ToolStripButton("m1");
btn.DisplayStyle = ToolStripItemDisplayStyle.Image;
btn.Image = (Image)O;
this.toolStrip1.Items.Add(btn);
this.Controls.Add(this.toolStrip1);
ResourceManager will work if your image is in a resource file. If it is just a file in your project (let's say the root) you can get it using something like this:
System.Reflection.Assembly assembly = System.Reflection.Assembly.GetExecutingAssembly();
System.IO.Stream file = assembly .GetManifestResourceStream("AssemblyName." + channel);
this.pictureBox1.Image = Image.FromStream(file);
Or if you're in WPF:
private ImageSource GetImage(string channel)
{
StreamResourceInfo sri = Application.GetResourceStream(new Uri("/TestApp;component/" + channel, UriKind.Relative));
BitmapImage bmp = new BitmapImage();
bmp.BeginInit();
bmp.StreamSource = sri.Stream;
bmp.EndInit();
return bmp;
}
Source: Stackoverflow.com