from array import array
listA = list(range(0,50))
for item in listA:
print(item)
arrayA = array("i", listA)
for item in arrayA:
print(item)
if variable b has a list then you can simply do the below:
create a new variable "a" as: a=[]
then assign the list to "a" as: a=b
now "a" has all the components of list "b" in array.
so you have successfully converted list to array.
I wanted a way to do this without using an extra module. First turn list to string, then append to an array:
dataset_list = ''.join(input_list)
dataset_array = []
for item in dataset_list.split(';'): # comma, or other
dataset_array.append(item)
Use the following code:
import numpy as np
myArray=np.array([1,2,4]) #func used to convert [1,2,3] list into an array
print(myArray)
If all you want is calling ravel
on your (nested, I s'pose?) list, you can do that directly, numpy
will do the casting for you:
L = [[1,None,3],["The", "quick", object]]
np.ravel(L)
# array([1, None, 3, 'The', 'quick', <class 'object'>], dtype=object)
Also worth mentioning that you needn't go through numpy
at all.
Source: Stackoverflow.com