Let say this is my JSON Object
{
"LabelData": {
"slogan": "AWAKEN YOUR SENSES",
"jobsearch": "JOB SEARCH",
"contact": "CONTACT",
"video": "ENCHANTING BEACHSCAPES",
"createprofile": "CREATE PROFILE"
}
}
I need to know that either 'video` exists or not in this Object, and if it exists i need to get the value of this key. I have tried following, but i am unable to get value of this key.
containerObject= new JSONObject(container);
if(containerObject.hasKey("video")){
//get Value of video
}
This question is related to
java
android
json
performance
android-layout
Please try this one..
JSONObject jsonObject= null;
try {
jsonObject = new JSONObject("result........");
String labelDataString=jsonObject.getString("LabelData");
JSONObject labelDataJson= null;
labelDataJson= new JSONObject(labelDataString);
if(labelDataJson.has("video")&&labelDataJson.getString("video")!=null){
String video=labelDataJson.getString("video");
}
} catch (JSONException e) {
e.printStackTrace();
}
JSONObject root= new JSONObject();
JSONObject container= root.getJSONObject("LabelData");
try{
//if key will not be available put it in the try catch block your program
will work without error
String Video=container.getString("video");
}
catch(JsonException e){
if key will not be there then this block will execute
}
if(video!=null || !video.isEmpty){
//get Value of video
}else{
//other vise leave it
}
i think this might help you
Try
private boolean hasKey(JSONObject jsonObject, String key) {
return jsonObject != null && jsonObject.has(key);
}
try {
JSONObject jsonObject = new JSONObject(yourJson);
if (hasKey(jsonObject, "labelData")) {
JSONObject labelDataJson = jsonObject.getJSONObject("LabelData");
if (hasKey(labelDataJson, "video")) {
String video = labelDataJson.getString("video");
}
}
} catch (JSONException e) {
}
Use:
if (containerObject.has("video")) {
//get value of video
}
containerObject = new JSONObject(container);
if (containerObject.has("video")) {
//get Value of video
}
From the structure of your source Object, I would try:
containerObject= new JSONObject(container);
if(containerObject.has("LabelData")){
JSONObject innerObject = containerObject.getJSONObject("LabelData");
if(innerObject.has("video")){
//Do with video
}
}
JSONObject class has a method named "has". Returns true if this object has a mapping for name. The mapping may be NULL. http://developer.android.com/reference/org/json/JSONObject.html#has(java.lang.String)
Source: Stackoverflow.com