How to count the number of words in a sentence ignoring numbers punctuation and whitespace

Question

How would I go about counting the words in a sentence  I m using Python   For example  I might have the string    string    I     am having  a   very  nice  23         day      That would be 7 words  I m having trouble with the random amount of spaces after before each word as well as when numbers or symbols are involved

User · Answer

How about using a simple loop to count the occurrences of number of spaces!?

_x000D_

txt = "Just an example here move along" _x000D_
count = 1_x000D_
for i in txt:_x000D_
if i == " ":_x000D_
   count += 1_x000D_
print(count)

_x000D_

User · Answer

import string   sentence    I     am having  a   very  nice  23         day      Remove all punctuations sentence   sentence translate str maketrans         string punctuation     Remove all numbers  sentence      join  word for word in sentence if not word isdigit     count   0  for index in range len sentence -1        if sentence index 1  isspace   and not sentence index  isspace            count    1  print count

User · Answer

str split   without any arguments splits on runs of whitespace characters    gt  gt  gt  s    I am having a very nice day    gt  gt  gt    gt  gt  gt  len s split    7   From the linked documentation      If sep is not specified or is None  a different splitting algorithm is applied  runs of consecutive whitespace are regarded as a single separator  and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace

User · Answer

You can use regex findall     import re line     I am having a very nice day   count   len re findall r  w    line   print  count

User · Answer

Ok here is my version of doing this  I noticed that you want your output to be 7  which means you dont want to count special characters and numbers  So here is regex pattern   re findall   a-zA-Z      string    Where  a-zA-Z   means it will match any character beetwen a-z  lowercase  and A-Z  upper case       About spaces  If you want to remove all extra spaces  just do   string   string rstrip   lstrip     Remove all extra spaces at the start and at the end of the string while      in string    While  there are 2 spaces beetwen words in our string        string   string replace                  replace them by one space

User · Answer

def wordCount mystring             tempcount   0           count   1            try                for character in mystring                    if character                               tempcount   1                       if tempcount   1                            count   1                        else                            tempcount   1                  else                       tempcount 0               return count             except Exception                 error    Not a string                 return error        mystring    I   am having   a    very nice 23         day                   print wordCount mystring       output is 8

User · Answer

s    I     am having  a   very  nice  23         day    sum  i strip string punctuation  isalpha   for i in s split       The statement above will go through each chunk of text and remove punctuations before verifying if the chunk is really string of alphabets

User · Answer

This is a simple word counter using regex  The script includes a loop which you can terminate it when you re done    word counter using regex import re while True      string  raw input  Enter the string         count   len re findall   a-zA-Z      string       if line     Done    command to terminate the loop         break     print  count  print   Terminated

[python] How to count the number of words in a sentence, ignoring numbers, punctuation and whitespace?

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