[python] How to sort Counter by value? - python

Yes:

>>> from collections import Counter
>>> x = Counter({'a':5, 'b':3, 'c':7})

Using the sorted keyword key and a lambda function:

>>> sorted(x.items(), key=lambda i: i[1])
[('b', 3), ('a', 5), ('c', 7)]
>>> sorted(x.items(), key=lambda i: i[1], reverse=True)
[('c', 7), ('a', 5), ('b', 3)]

This works for all dictionaries. However Counter has a special function which already gives you the sorted items (from most frequent, to least frequent). It's called most_common():

>>> x.most_common()
[('c', 7), ('a', 5), ('b', 3)]
>>> list(reversed(x.most_common()))  # in order of least to most
[('b', 3), ('a', 5), ('c', 7)]

You can also specify how many items you want to see:

>>> x.most_common(2)  # specify number you want
[('c', 7), ('a', 5)]

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