time data does not match format

Question

I get the following error   time data  07 28 2014 18 54 55 099000  does not match format   d  m  Y  H  M  S  f    But I cannot see what parameter is wrong in  d  m  Y  H  M  S  f    This is the code I use   from datetime import datetime time value   datetime strptime csv line 0     000     d  m  Y  H  M  S  f     I have added and removed the 000 but I get the same error

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I had a similar error - time data  01-07-2020  does not match format   d m Y   match   I didn t know that I have to use a hyphen in the format parameter  This worked for me - df  Date     pd to datetime df  Date    format   d- m- Y

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You have the month and day swapped     m  d  Y  H  M  S  f    28 will never fit in the range for the  m month parameter otherwise   With  m and  d in the correct order parsing works    gt  gt  gt  from datetime import datetime  gt  gt  gt  datetime strptime  07 28 2014 18 54 55 099000     m  d  Y  H  M  S  f   datetime datetime 2014  7  28  18  54  55  99000    You don t need to add  000    f can parse shorter numbers correctly    gt  gt  gt  datetime strptime  07 28 2014 18 54 55 099     m  d  Y  H  M  S  f   datetime datetime 2014  7  28  18  54  55  99000

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I had a case where solution was hard to figure out  This is not exactly relevant to particular question  but might help someone looking to solve a case with same error message when strptime is fed with timezone information  In my case  the reason for throwing  ValueError  time data  2016-02-28T08 27 16 000-07 00  does not match format   Y- m- dT H  M  S  f z   was presence of last colon in the timezone part  While in some locales  Russian one  for example  code was able to execute well  in another  English one  it was failing  Removing the last colon helped remedy my situation

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While the above answer is 100  helpful and correct  I d like to add the following since only a combination of the above answer and reading through the pandas doc helped me   2-digit   4-digit year  It is noteworthy  that in order to parse through a 2-digit year  e g   90  rather than  1990   a  y is required instead of a  Y    Infer the datetime automatically  If parsing with a pre-defined format still doesn t work for you  try using the flag infer datetime format True  for example   yields df  Date     pd to datetime yields df  Date    infer datetime format True    Be advised that this solution is slower than using a pre-defined format

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I had the exact same error but with slightly different format and root-cause  and since this is the first Q amp A that pops up when you search for  time data does not match format   I thought I d leave the mistake I made for future viewers    My initial code    start   datetime strptime  05-SEP-19 00 00 00 000 AM     d- b- y  I  M  S  f  p     Where I used  I to parse the hours and  p to parse  AM PM     The error       ValueError  time data  05-SEP-19 00 00 00 000000 AM  does not match format   d- b- y  I  M  S  f  p    I was going through the datetime docs and finally realized in 12-hour format  I  there is no 00    once I changed 00 00 00 to 12 00 00  the problem was resolved    So it s either 01-12 using  I with  p  or 00-23 using  H

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No need to use datetime library  Using the dateutil library there is no need of any format    gt  gt  gt  from dateutil import parser  gt  gt  gt  s   25 April  2020  2 50  pm  IST   gt  gt  gt  parser parse s  datetime datetime 2020  4  25  14  50

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To compare date time  you can try this  Datetime format can be changed   from datetime import datetime   gt  gt  gt  a   datetime strptime  10 12 2013     m  d  Y    gt  gt  gt  b   datetime strptime  10 15 2013     m  d  Y    gt  gt  gt  a gt b False

[python] time data does not match format

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