Ubound can return the max index value of an array, but in a multidimensional array, how would I specify WHICH dimension I want the max index of?
For example
Dim arr(1 to 4, 1 to 3) As Variant
In this 4x3 array, how would I have Ubound return 4, and how would I have Ubound return 3?
You need to deal with the optional Rank parameter of UBound
.
Dim arr(1 To 4, 1 To 3) As Variant
Debug.Print UBound(arr, 1) '? returns 4
Debug.Print UBound(arr, 2) '? returns 3
More at: UBound Function (Visual Basic)
Looping D3 ways;
Sub SearchArray()
Dim arr(3, 2) As Variant
arr(0, 0) = "A"
arr(0, 1) = "1"
arr(0, 2) = "w"
arr(1, 0) = "B"
arr(1, 1) = "2"
arr(1, 2) = "x"
arr(2, 0) = "C"
arr(2, 1) = "3"
arr(2, 2) = "y"
arr(3, 0) = "D"
arr(3, 1) = "4"
arr(3, 2) = "z"
Debug.Print "Loop Dimension 1"
For i = 0 To UBound(arr, 1)
Debug.Print "arr(" & i & ", 0) is " & arr(i, 0)
Next i
Debug.Print ""
Debug.Print "Loop Dimension 2"
For j = 0 To UBound(arr, 2)
Debug.Print "arr(0, " & j & ") is " & arr(0, j)
Next j
Debug.Print ""
Debug.Print "Loop Dimension 1 and 2"
For i = 0 To UBound(arr, 1)
For j = 0 To UBound(arr, 2)
Debug.Print "arr(" & i & ", " & j & ") is " & arr(i, j)
Next j
Next i
Debug.Print ""
End Sub
[This is a late answer addressing the title of the question (since that is what people would encounter when searching) rather than the specifics of OP's question which has already been answered adequately]
Ubound
is a bit fragile in that it provides no way to know how many dimensions an array has. You can use error trapping to determine the full layout of an array. The following returns a collection of arrays, one for each dimension. The count
property can be used to determine the number of dimensions and their lower and upper bounds can be extracted as needed:
Function Bounds(A As Variant) As Collection
Dim C As New Collection
Dim v As Variant, i As Long
On Error GoTo exit_function
i = 1
Do While True
v = Array(LBound(A, i), UBound(A, i))
C.Add v
i = i + 1
Loop
exit_function:
Set Bounds = C
End Function
Used like this:
Sub test()
Dim i As Long
Dim A(1 To 10, 1 To 5, 4 To 10) As Integer
Dim B(1 To 5) As Variant
Dim C As Variant
Dim sizes As Collection
Set sizes = Bounds(A)
Debug.Print "A has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
Set sizes = Bounds(B)
Debug.Print vbCrLf & "B has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
Set sizes = Bounds(C)
Debug.Print vbCrLf & "C has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
End Sub
Output:
A has 3 dimensions:
1 to 10
1 to 5
4 to 10
B has 1 dimensions:
1 to 5
C has 0 dimensions:
In addition to the already excellent answers, also consider this function to retrieve both the number of dimensions and their bounds, which is similar to John's answer, but works and looks a little differently:
Function sizeOfArray(arr As Variant) As String
Dim str As String
Dim numDim As Integer
numDim = NumberOfArrayDimensions(arr)
str = "Array"
For i = 1 To numDim
str = str & "(" & LBound(arr, i) & " To " & UBound(arr, i)
If Not i = numDim Then
str = str & ", "
Else
str = str & ")"
End If
Next i
sizeOfArray = str
End Function
Private Function NumberOfArrayDimensions(arr As Variant) As Integer
' By Chip Pearson
' http://www.cpearson.com/excel/vbaarrays.htm
Dim Ndx As Integer
Dim Res As Integer
On Error Resume Next
' Loop, increasing the dimension index Ndx, until an error occurs.
' An error will occur when Ndx exceeds the number of dimension
' in the array. Return Ndx - 1.
Do
Ndx = Ndx + 1
Res = UBound(arr, Ndx)
Loop Until Err.Number <> 0
NumberOfArrayDimensions = Ndx - 1
End Function
Example usage:
Sub arrSizeTester()
Dim arr(1 To 2, 3 To 22, 2 To 9, 12 To 18) As Variant
Debug.Print sizeOfArray(arr())
End Sub
And its output:
Array(1 To 2, 3 To 22, 2 To 9, 12 To 18)
Source: Stackoverflow.com