Unable to obtain LocalDateTime from TemporalAccessor when parsing LocalDateTime Java 8

Question

I am simply trying to convert a date string into a DateTime object in Java 8  Upon running the following lines   DateTimeFormatter formatter   DateTimeFormatter ofPattern  yyyyMMdd    LocalDateTime dt   LocalDateTime parse  20140218   formatter     I get the following error   Exception in thread  main  java time format DateTimeParseException   Text  20140218  could not be parsed   Unable to obtain LocalDateTime from TemporalAccessor      ISO resolved to 2014-02-18 of type java time format Parsed     at java time format DateTimeFormatter createError DateTimeFormatter java 1918      at java time format DateTimeFormatter parse DateTimeFormatter java 1853      at java time LocalDateTime parse LocalDateTime java 492    The syntax is identical to what has been suggested here  yet I am served with an exception  I am using JDK-8u25

User · Answer

For anyone who landed here with this error, like I did:

Unable to obtain LocalDateTime from TemporalAccessor: {HourOfAmPm=0, MinuteOfHour=0}

It came from a the following line:

LocalDateTime.parse(date, DateTimeFormatter.ofPattern("M/d/yy h:mm"));

It turned out that it was because I was using a 12hr Hour pattern on a 0 hour, instead of a 24hr pattern.

Changing the hour to 24hr pattern by using a capital H fixes it:

LocalDateTime.parse(date, DateTimeFormatter.ofPattern("M/d/yy H:mm"));

User · Answer

Try this one   DateTimeFormatter dateTimeFormatter   DateTimeFormatter ofPattern  MM-dd-yyyy     LocalDate fromLocalDate   LocalDate parse fromdstrong textate  dateTimeFormatter     You can add any format you want  That works for me

User · Answer

This works fine  public class DateDemo       public static void main String   args            DateTimeFormatter formatter   DateTimeFormatter ofPattern  dd-MM-yyyy hh mm            String date    16-08-2018 12 10           LocalDate localDate   LocalDate parse date  formatter           System out println  VALUE   localDate            DateTimeFormatter formatter1   DateTimeFormatter ofPattern  dd-MM-yyyy HH mm            LocalDateTime parse   LocalDateTime parse date  formatter1           System out println  VALUE1   parse             output   VALUE 2018-08-16 VALUE1 2018-08-16T12 10

User · Answer

Expanding on retrography s answer    I had this same problem even when using LocalDate and not LocalDateTime  The issue was that I had created my DateTimeFormatter using  withResolverStyle ResolverStyle STRICT    so I had to use date pattern uuuuMMdd instead of yyyyMMdd  i e   year  instead of  year-of-era     DateTimeFormatter formatter   new DateTimeFormatterBuilder      parseStrict      appendPattern  uuuuMMdd      toFormatter      withResolverStyle ResolverStyle STRICT   LocalDate dt   LocalDate parse  20140218   formatter      This solution was originally a comment to retrography s answer  but I was encouraged to post it as a stand-alone answer because it apparently works really well for many people

User · Answer

It turns out Java does not accept a bare Date value as DateTime  Using LocalDate instead of LocalDateTime solves the issue   DateTimeFormatter formatter   DateTimeFormatter ofPattern  yyyyMMdd    LocalDate dt   LocalDate parse  20140218   formatter

User · Answer

If you really need to transform a date to a LocalDateTime object  you could use the LocalDate atStartOfDay    This will give you a LocalDateTime object at the specified date  having the hour  minute and second fields set to 0    final DateTimeFormatter formatter   DateTimeFormatter ofPattern  yyyyMMdd    LocalDateTime time   LocalDate parse  20140218   formatter  atStartOfDay

User · Answer

If the date String does not include any value for hours  minutes and etc you cannot directly convert this to a LocalDateTime  You can only convert it to a LocalDate  because the string only represent the year month and date components it would be the correct thing to do   DateTimeFormatter dtf   DateTimeFormatter ofPattern  yyyyMMdd    LocalDate ld   LocalDate parse  20180306   dtf      2018-03-06   Anyway you can convert this to LocalDateTime   DateTimeFormatter dtf   DateTimeFormatter ofPattern  yyyyMMdd    LocalDate ld   LocalDate parse  20180306   dtf   LocalDateTime ldt   LocalDateTime of ld  LocalTime of 0 0       2018-03-06T00 00

User · Answer

This is a really unclear and unhelpful error message  After much trial and error I found that LocalDateTime will give the above error if you do not attempt to parse a time  By using LocalDate instead  it works without erroring   This is poorly documented and the related exception is very unhelpful

User · Answer

For what is worth if anyone should read again this topic like me  the correct answer would be in DateTimeFormatter definition  e g    private static DateTimeFormatter DATE FORMAT                 new DateTimeFormatterBuilder   appendPattern  dd MM yyyy   HH   mm   ss   SSS                  parseDefaulting ChronoField HOUR OF DAY  0               parseDefaulting ChronoField MINUTE OF HOUR  0               parseDefaulting ChronoField SECOND OF MINUTE  0               toFormatter       One should set the optional fields if they will appear  And the rest of code should be exactly the same

[java] Unable to obtain LocalDateTime from TemporalAccessor when parsing LocalDateTime (Java 8)

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