I use Spring boot+JPA and having a problem while starting the service.
Caused by: java.lang.IllegalArgumentException: Not an managed type: class com.nervytech.dialer.domain.PhoneSettings
at org.hibernate.jpa.internal.metamodel.MetamodelImpl.managedType(MetamodelImpl.java:219)
at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation.<init>(JpaMetamodelEntityInformation.java:68)
at org.springframework.data.jpa.repository.support.JpaEntityInformationSupport.getMetadata(JpaEntityInformationSupport.java:65)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getEntityInformation(JpaRepositoryFactory.java:145)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:89)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:69)
at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:177)
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.initAndReturn(RepositoryFactoryBeanSupport.java:239)
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.afterPropertiesSet(RepositoryFactoryBeanSupport.java:225)
at org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean.afterPropertiesSet(JpaRepositoryFactoryBean.java:92)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1625)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1562)
Here is the Application.java file,
@Configuration
@ComponentScan
@EnableAutoConfiguration(exclude = { DataSourceAutoConfiguration.class })
@SpringBootApplication
public class DialerApplication {
public static void main(String[] args) {
SpringApplication.run(DialerApplication.class, args);
}
}
I use UCp for connection pooling and the DataSource configuration is below,
@Configuration
@ComponentScan
@EnableTransactionManagement
@EnableAutoConfiguration
@EnableJpaRepositories(entityManagerFactoryRef = "dialerEntityManagerFactory", transactionManagerRef = "dialerTransactionManager", basePackages = { "com.nervy.dialer.spring.jpa.repository" })
public class ApplicationDataSource {
/** The Constant LOGGER. */
private static final Logger LOGGER = LoggerFactory
.getLogger(ApplicationDataSource.class);
/** The Constant TEST_SQL. */
private static final String TEST_SQL = "select 1 from dual";
/** The pooled data source. */
private PoolDataSource pooledDataSource;
UserDetailsService Implementation,
@Service("userDetailsService")
@SessionAttributes("user")
public class UserDetailsServiceImpl implements UserDetailsService {
@Autowired
private UserService userService;
Service layer implementation,
@Service
public class PhoneSettingsServiceImpl implements PhoneSettingsService {
}
The repository class,
@Repository
public interface PhoneSettingsRepository extends JpaRepository<PhoneSettings, Long> {
}
Entity class,
@Entity
@Table(name = "phone_settings", catalog = "dialer")
public class PhoneSettings implements java.io.Serializable {
WebSecurityConfig class,
@Configuration
@EnableWebMvcSecurity
@ComponentScan
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private UserDetailsServiceImpl userDetailsService;
/**
* Instantiates a new web security config.
*/
public WebSecurityConfig() {
super();
}
/**
* {@inheritDoc}
* @see org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter#configure(org.springframework.security.config.annotation.web.builders.HttpSecurity)
*/
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests()
.antMatchers("/login", "/logoffUser", "/sessionExpired", "/error", "/unauth", "/redirect", "*support*").permitAll()
.anyRequest().authenticated().and().rememberMe().and().httpBasic()
.and()
.csrf()
.disable().logout().deleteCookies("JSESSIONID").logoutSuccessUrl("/logoff").invalidateHttpSession(true);
}
@Autowired
public void configAuthentication(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userDetailsService).passwordEncoder(new BCryptPasswordEncoder());
}
}
The packages are as follows,
Application
class is in - com.nervy.dialer
Datasource
class is in - com.nervy.dialer.common
com.nervy.dialer.domain
com.nervy.dialer.domain.service.impl
com.nervy.dialer.spring.controller
com.nervy.dialer.spring.jpa.repository
WebSecurityConfig
is in - com.nervy.dialer.spring.security
Thanks
This question is related to
spring
spring-mvc
jpa
spring-boot
spring-data
Configure the location of entities using @EntityScan in Spring Boot entry point class.
Update on Sept 2016: For Spring Boot 1.4+:
use org.springframework.boot.autoconfigure.domain.EntityScan
instead of org.springframework.boot.orm.jpa.EntityScan
, as ...boot.orm.jpa.EntityScan is deprecated as of Spring Boot 1.4
You either missed @Entity on class definition or you have explicit component scan path and this path does not contain your class
Try adding All the following, In my application it is working fine with tomcat
@EnableJpaRepositories("my.package.base.*")
@ComponentScan(basePackages = { "my.package.base.*" })
@EntityScan("my.package.base.*")
I am using spring boot, and when i am using embedded tomcat it was working fine with out @EntityScan("my.package.base.*")
but when I tried to deploy the app to an external tomcat I got not a managed type
error for my entity.
You can use @EntityScan annotation and provide your entity package for scanning all your jpa entities. You can use this annotation on your base application class where you have used @SpringBootApplication annotation.
e.g. @EntityScan("com.test.springboot.demo.entity")
I got this error because I stupidly wrote
public interface FooBarRepository extends CrudRepository<FooBarRepository, Long> { ...
A brief explanation: One typically creates a FooBarRepository class to manage FooBar objects (often representing data in a table called something like foo_bar.) When extending the CrudRepository to create the specialized repository class, one needs to specify the type that's being managed -- in this case, FooBar. What I mistakenly typed, though, was FooBarRepository rather than FooBar. FooBarRepository is not the type (the class) I'm trying to manage with the FooBarRepository. Therefore, the compiler issues this error.
I highlighted the mistaken bit of typing in bold. Delete the highlighted word Repository in my example and the code compiles.
Faced similar issue. In my case the repository and the type being managed where not in same package.
I had this same problem but only when running spring boot tests cases that required JPA. The end result was that our own jpa test configuration was initializing an EntityManagerFactory and setting the packages to scan. This evidently will override the EntityScan parameters if you are setting it manually.
final LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setJpaVendorAdapter( vendorAdapter );
factory.setPackagesToScan( Project.class.getPackage().getName());
factory.setDataSource( dataSource );
Important to note: if you are still stuck you should set a break point in the org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager
on the setPackagesToScan()
method and take a look at where this is being called and what packages are being passed to it.
I am using spring boot 2.0 and I fixed this by replacing @ComponentScan with @EntityScan
never forget to add @Entity on domain class
I had some problem while migrating from Spring boot 1.3.x to 1.5, I got it working after updating entity package at EntityManagerFactory bean
@Bean(name="entityManagerFactoryDef")
@Primary
public LocalContainerEntityManagerFactoryBean defaultEntityManager() {
Map map = new HashMap();
map.put("hibernate.default_schema", env.getProperty("spring.datasource.username"));
map.put("hibernate.hbm2ddl.auto", env.getProperty("spring.jpa.hibernate.ddl-auto"));
LocalContainerEntityManagerFactoryBean em = createEntityManagerFactoryBuilder(jpaVendorProperties())
.dataSource(primaryDataSource()).persistenceUnit("default").properties(map).build();
em.setPackagesToScan("com.simple.entity");
em.afterPropertiesSet();
return em;
}
This bean referred in Application class as below
@SpringBootApplication
@EnableJpaRepositories(entityManagerFactoryRef = "entityManagerFactoryDef")
public class SimpleApp {
}
Put this in your Application.java
file
@ComponentScan(basePackages={"com.nervy.dialer"})
@EntityScan(basePackages="domain")
I had this problem because I didn't map all entities in orm.xml file
I have moved my application class to parent package like :
Main class: com.job.application
Entity: com.job.application.entity
This way you don't have to add @EntityScan
I have the same probblem, in version spring boot v1.3.x what i did is upgrade spring boot to version 1.5.7.RELEASE. Then the probblem gone.
If you configure your own EntityManagerFactory Bean or if you have copy-pasted such a persistence configuration from another project, you must set or adapt the package in EntityManagerFactory's configuration:
@Bean
public EntityManagerFactory entityManagerFactory() throws PropertyVetoException {
HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
vendorAdapter.setGenerateDdl(true);
LocalContainerEntityManagerFactoryBean factory;
factory = new LocalContainerEntityManagerFactoryBean();
factory.setPackagesToScan("!!!!!!package.path.to.entities!!!!!");
//...
}
In my case the problem was due to my forgetting to have annotated my Entity classes with @javax.persistence.Entity
annotation. Doh!
//The class reported as "not a amanaged type"
@javax.persistence.Entity
public class MyEntityClass extends my.base.EntityClass {
....
}
Below worked for me..
import static org.springframework.test.web.servlet.request.MockMvcRequestBuilders.get;
import static org.springframework.test.web.servlet.result.MockMvcResultHandlers.print;
import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status;
import org.apache.catalina.security.SecurityConfig;
import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.autoconfigure.domain.EntityScan;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.test.context.junit4.SpringRunner;
import org.springframework.test.context.web.WebAppConfiguration;
import org.springframework.test.web.servlet.MockMvc;
import org.springframework.test.web.servlet.setup.MockMvcBuilders;
import org.springframework.web.context.WebApplicationContext;
import com.something.configuration.SomethingConfig;
@RunWith(SpringRunner.class)
@SpringBootTest(classes = { SomethingConfig.class, SecurityConfig.class }) //All your configuration classes
@EnableAutoConfiguration
@WebAppConfiguration // for MVC configuration
@EnableJpaRepositories("com.something.persistence.dataaccess") //JPA repositories
@EntityScan("com.something.domain.entity.*") //JPA entities
@ComponentScan("com.something.persistence.fixture") //any component classes you have
public class SomethingApplicationTest {
@Autowired
private WebApplicationContext ctx;
private MockMvc mockMvc;
@Before
public void setUp() {
this.mockMvc = MockMvcBuilders.webAppContextSetup(ctx).build();
}
@Test
public void loginTest() throws Exception {
this.mockMvc.perform(get("/something/login"))
.andDo(print()).andExpect(status().isOk());
}
}
Source: Stackoverflow.com