[php] How do I extract data from JSON with PHP?

This is intended to be a general reference question and answer covering many of the never-ending "How do I access data in my JSON?" questions. It is here to handle the broad basics of decoding JSON in PHP and accessing the results.

I have the JSON:

{
    "type": "donut",
    "name": "Cake",
    "toppings": [
        { "id": "5002", "type": "Glazed" },
        { "id": "5006", "type": "Chocolate with Sprinkles" },
        { "id": "5004", "type": "Maple" }
    ]
}

How do I decode this in PHP and access the resulting data?

This question is related to php json

The answer is


We can decode json string into array using json_decode function in php

1) json_decode($json_string) // it returns object

2) json_decode($json_string,true) // it returns array

$json_string = '{
    "type": "donut",
    "name": "Cake",
    "toppings": [
        { "id": "5002", "type": "Glazed" },
        { "id": "5006", "type": "Chocolate with Sprinkles" },
        { "id": "5004", "type": "Maple" }
    ]
}';
$array = json_decode($json_string,true);

echo $array['type']; //it gives donut

You can use json_decode() to convert a json string to a PHP object/array.

Eg.

Input:

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

var_dump(json_decode($json));
var_dump(json_decode($json, true));

Output:

object(stdClass)#1 (5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

array(5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

Few Points to remember:

  • json_decode requires the string to be a valid json else it will return NULL.
  • In the event of a failure to decode, json_last_error() can be used to determine the exact nature of the error.
  • Make sure you pass in utf8 content, or json_decode may error out and just return a NULL value.

Consider using JSONPath https://packagist.org/packages/flow/jsonpath

There is a pretty clear explanation of how to use it and parse a JSON-file avoiding all the loops proposed. If you are familiar with XPath for XML you will start loving this approach.


https://paiza.io/projects/X1QjjBkA8mDo6oVh-J_63w

Check below code for converting json to array in PHP, If JSON is correct then json_decode() works well, and will return an array, But if malformed JSON, then It will return NULL,

<?php
function jsonDecode1($json){
    $arr = json_decode($json, true);
    return $arr;
}

// In case of malformed JSON, it will return NULL
var_dump( jsonDecode1($json) );

If malformed JSON, and you are expecting only array, then you can use this function,

<?php
function jsonDecode2($json){
    $arr = (array) json_decode($json, true);
    return $arr;
}

// In case of malformed JSON, it will return an empty array()
var_dump( jsonDecode2($json) );

If malformed JSON, and you want to stop code execution, then you can use this function,

<?php
function jsonDecode3($json){
    $arr = (array) json_decode($json, true);

    if(empty(json_last_error())){
        return $arr;
    }
    else{
        throw new ErrorException( json_last_error_msg() );
    }
}

// In case of malformed JSON, Fatal error will be generated
var_dump( jsonDecode3($json) );

You can use any function depends on your requirement,


The acepted Answer is very detailed and correct in most of the cases.

I just want to add that i was getting an error while attempting to load a JSON text file encoded with UTF8, i had a well formatted JSON but the 'json_decode' always returned me with NULL, it was due the BOM mark.

To solve it, i made this PHP function:

function load_utf8_file($filePath)
{
    $response = null;
    try
    {
        if (file_exists($filePath)) {
            $text = file_get_contents($filePath);
            $response = preg_replace("/^\xEF\xBB\xBF/", '', $text);          
        }     
    } catch (Exception $e) {
      echo 'ERROR: ',  $e->getMessage(), "\n";
   }
   finally{  }
   return $response;
}

Then i use it like this to load a JSON file and get a value from it:

$str = load_utf8_file('appconfig.json'); 
$json = json_decode($str, true); 
//print_r($json);
echo $json['prod']['deploy']['hostname'];

// Using json as php array 

$json = '[{"user_id":"1","user_name":"Sayeed Amin","time":"2019-11-06 13:21:26"}]';

//or use from file
//$json = file_get_contents('results.json');

$someArray = json_decode($json, true);

foreach ($someArray as $key => $value) {
    echo $value["user_id"] . ", " . $value["user_name"] . ", " . $value["time"] . "<br>";
}