[c] Output single character in C

When printing a single character in a C program, must I use "%1s" in the format string? Can I use something like "%c"?

char variable = 'x';  // the variable is a char whose value is lowercase x

printf("<%c>", variable); // print it with angle brackets around the character

yes, %c will print a single char:

printf("%c", 'h');

also, putchar/putc will work too. From "man putchar":

#include <stdio.h>

int fputc(int c, FILE *stream);
int putc(int c, FILE *stream);
int putchar(int c);

* fputc() writes the character c, cast to an unsigned char, to stream.
* putc() is equivalent to fputc() except that it may be implemented as a macro which evaluates stream more than once.
* putchar(c); is equivalent to putc(c,stdout).

EDIT:

Also note, that if you have a string, to output a single char, you need get the character in the string that you want to output. For example:

const char *h = "hello world";
printf("%c\n", h[4]); /* outputs an 'o' character */

The easiest way to output a single character is to simply use the putchar function. After all, that's it's sole purpose and it cannot do anything else. It cannot be simpler than that.

yes, %c will print a single char:

printf("%c", 'h');

also, putchar/putc will work too. From "man putchar":

#include <stdio.h>

int fputc(int c, FILE *stream);
int putc(int c, FILE *stream);
int putchar(int c);

* fputc() writes the character c, cast to an unsigned char, to stream.
* putc() is equivalent to fputc() except that it may be implemented as a macro which evaluates stream more than once.
* putchar(c); is equivalent to putc(c,stdout).

EDIT:

Also note, that if you have a string, to output a single char, you need get the character in the string that you want to output. For example:

const char *h = "hello world";
printf("%c\n", h[4]); /* outputs an 'o' character */

Be careful of difference between 'c' and "c"

'c' is a char suitable for formatting with %c

"c" is a char* pointing to a memory block with a length of 2 (with the null terminator).

As mentioned in one of the other answers, you can use putc(int c, FILE *stream), putchar(int c) or fputc(int c, FILE *stream) for this purpose.

What's important to note is that using any of the above functions is from some to signicantly faster than using any of the format-parsing functions like printf.

Using printf is like using a machine gun to fire one bullet.

yes, %c will print a single char:

printf("%c", 'h');

also, putchar/putc will work too. From "man putchar":

#include <stdio.h>

int fputc(int c, FILE *stream);
int putc(int c, FILE *stream);
int putchar(int c);

* fputc() writes the character c, cast to an unsigned char, to stream.
* putc() is equivalent to fputc() except that it may be implemented as a macro which evaluates stream more than once.
* putchar(c); is equivalent to putc(c,stdout).

EDIT:

Also note, that if you have a string, to output a single char, you need get the character in the string that you want to output. For example:

const char *h = "hello world";
printf("%c\n", h[4]); /* outputs an 'o' character */

Be careful of difference between 'c' and "c"

'c' is a char suitable for formatting with %c

"c" is a char* pointing to a memory block with a length of 2 (with the null terminator).

As mentioned in one of the other answers, you can use putc(int c, FILE *stream), putchar(int c) or fputc(int c, FILE *stream) for this purpose.

What's important to note is that using any of the above functions is from some to signicantly faster than using any of the format-parsing functions like printf.

Using printf is like using a machine gun to fire one bullet.

Be careful of difference between 'c' and "c"

'c' is a char suitable for formatting with %c

"c" is a char* pointing to a memory block with a length of 2 (with the null terminator).

char variable = 'x';  // the variable is a char whose value is lowercase x

printf("<%c>", variable); // print it with angle brackets around the character

Be careful of difference between 'c' and "c"

'c' is a char suitable for formatting with %c

"c" is a char* pointing to a memory block with a length of 2 (with the null terminator).

The easiest way to output a single character is to simply use the putchar function. After all, that's it's sole purpose and it cannot do anything else. It cannot be simpler than that.

As mentioned in one of the other answers, you can use putc(int c, FILE *stream), putchar(int c) or fputc(int c, FILE *stream) for this purpose.

What's important to note is that using any of the above functions is from some to signicantly faster than using any of the format-parsing functions like printf.

Using printf is like using a machine gun to fire one bullet.

char variable = 'x';  // the variable is a char whose value is lowercase x

printf("<%c>", variable); // print it with angle brackets around the character

As mentioned in one of the other answers, you can use putc(int c, FILE *stream), putchar(int c) or fputc(int c, FILE *stream) for this purpose.

What's important to note is that using any of the above functions is from some to signicantly faster than using any of the format-parsing functions like printf.

Using printf is like using a machine gun to fire one bullet.

yes, %c will print a single char:

printf("%c", 'h');

also, putchar/putc will work too. From "man putchar":

#include <stdio.h>

int fputc(int c, FILE *stream);
int putc(int c, FILE *stream);
int putchar(int c);

* fputc() writes the character c, cast to an unsigned char, to stream.
* putc() is equivalent to fputc() except that it may be implemented as a macro which evaluates stream more than once.
* putchar(c); is equivalent to putc(c,stdout).

EDIT:

Also note, that if you have a string, to output a single char, you need get the character in the string that you want to output. For example:

const char *h = "hello world";
printf("%c\n", h[4]); /* outputs an 'o' character */

char variable = 'x';  // the variable is a char whose value is lowercase x

printf("<%c>", variable); // print it with angle brackets around the character