Without bashisms (works even in the System V sh),
case $string in
''|*[!0-9]*) echo bad ;;
*) echo good ;;
esac
This rejects empty strings and strings containing non-digits, accepting everything else.
Negative or floating-point numbers need some additional work. An idea is to exclude -
/ .
in the first "bad" pattern and add more "bad" patterns containing the inappropriate uses of them (?*-*
/ *.*.*
)
This tests if a number is a non negative integer and is both shell independent (i.e. without bashisms) and uses only shell built-ins:
INCORRECT.
As this first answer (below) allows for integers with characters in them as long as the first are not first in the variable.
[ -z "${num##[0-9]*}" ] && echo "is a number" || echo "is not a number";
CORRECT .
As jilles commented and suggested in his answer this is the correct way to do it using shell-patterns.
[ ! -z "${num##*[!0-9]*}" ] && echo "is a number" || echo "is not a number";
Nobody suggested bash's extended pattern matching:
[[ $1 == ?(-)+([0-9]) ]] && echo "$1 is an integer"
or using new POSIX style:
[[ $1 == ?(-)+([:digit:]) ]] && echo "$1 is an integer"
The following solution can also be used in basic shells such as Bourne without the need for regular expressions. Basically any numeric value evaluation operations using non-numbers will result in an error which will be implicitly considered as false in shell:
"$var" -eq "$var"
as in:
#!/bin/bash
var=a
if [ -n "$var" ] && [ "$var" -eq "$var" ] 2>/dev/null; then
echo number
else
echo not a number
fi
You can can also test for $? the return code of the operation which is more explicit:
[ -n "$var" ] && [ "$var" -eq "$var" ] 2>/dev/null
if [ $? -ne 0 ]; then
echo $var is not number
fi
Redirection of standard error is there to hide the "integer expression expected" message that bash prints out in case we do not have a number.
CAVEATS (thanks to the comments below):
[[ ]]
instead of [ ]
will always evaluate to true
true
bash: [[: 1 a: syntax error in expression (error token is "a")
bash: [[: i: expression recursion level exceeded (error token is "i")
I found quite a short version:
function isnum()
{
return `echo "$1" | awk -F"\n" '{print ($0 != $0+0)}'`
}
Quick & Dirty: I know it's not the most elegant way, but I usually just added a zero to it and test the result. like so:
function isInteger {
[ $(($1+0)) != 0 ] && echo "$1 is a number" || echo "$1 is not a number"
}
x=1; isInteger $x
x="1"; isInteger $x
x="joe"; isInteger $x
x=0x16 ; isInteger $x
x=-32674; isInteger $x
$(($1+0)) will return 0 or bomb if $1 is NOT an integer. for Example:
function zipIt { # quick zip - unless the 1st parameter is a number
ERROR="not a valid number. "
if [ $(($1+0)) != 0 ] ; then # isInteger($1)
echo " backing up files changed in the last $1 days."
OUT="zipIt-$1-day.tgz"
find . -mtime -$1 -type f -print0 | xargs -0 tar cvzf $OUT
return 1
fi
showError $ERROR
}
NOTE: I guess I never thought to check for floats or mixed types that will make the entire script bomb... in my case, I didn't want it go any further. I'm gonna play around with mrucci's solution and Duffy's regex - they seem the most robust within the bash framework...
http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_04_03.html
You can also use bash's character classes.
if [[ $VAR = *[[:digit:]]* ]]; then
echo "$VAR is numeric"
else
echo "$VAR is not numeric"
fi
Numerics will include space, the decimal point, and "e" or "E" for floating point.
But, if you specify a C-style hex number, i.e. "0xffff" or "0XFFFF", [[:digit:]] returns true. A bit of a trap here, bash allows you do to something like "0xAZ00" and still count it as a digit (isn't this from some weird quirk of GCC compilers that let you use 0x notation for bases other than 16???)
You might want to test for "0x" or "0X" before testing if it's a numeric if your input is completely untrusted, unless you want to accept hex numbers. That would be accomplished by:
if [[ ${VARIABLE:1:2} = "0x" ]] || [[ ${VARIABLE:1:2} = "0X" ]]; then echo "$VAR is not numeric"; fi
This is a little rough around the edges but a little more novice friendly.
if [ $number -ge 0 ]
then
echo "Continue with code block"
else
echo "We matched 0 or $number is not a number"
fi
This will cause an error and print "Illegal number:" if $number is not a number but it will not break out of the script. Oddly there is not a test option I could find to just test for an integer. The logic here will match any number that is greater than or equal to 0.
Stack popped a message asked me if I really want to answer after 30+ answers? But of course!!! Use bash new features and here it is: (after the comment I made a change)
function isInt() { ([[ $1 -eq $(( $1 + 0 )) ]] 2>/dev/null && [[ $1 != '' ]] && echo 1) || echo '' }
function isInt() {
([[ $1 =~ ^[-+0-9]+$ ]] && [[ $1 -eq $(( $1 + 0 )) ]] 2>/dev/null && [[ $1 != '' ]] && echo 1) || echo ''
}
Supports:
===============out-of-the-box==================
1. negative integers (true & arithmetic),
2. positive integers (true & arithmetic),
3. with quotation (true & arithmetic),
4. without quotation (true & arithmetic),
5. all of the above with mixed signs(!!!) (true & arithmetic),
6. empty string (false & arithmetic),
7. no value (false & arithmetic),
8. alphanumeric (false & no arithmetic),
9. mixed only signs (false & no arithmetic),
================problematic====================
10. positive/negative floats with 1 decimal (true & NO arithmetic),
11. positive/negative floats with 2 or more decimals (FALSE & NO arithmetic).
True/false is what you get from the function only when used combined with process substitution like in [[ $( isInt <arg> ) ]]
as there is no logical type in bash neither return value of function.
I use capital when the result of the test expression is WRONG whereas, it should be the reverse!
By 'arithmetic' I mean bash can do math like in this expression: $x=$(( $y + 34))
.
I use 'arithmetic/no arithmetic' when in mathematical expressions the argument acts as it is expected and 'NO arithmetic' when it misbehaves compared with what it is expected.
As you see, only no 10 and 11 are the problematic ones!
Perfect!
PS: Note that the MOST popular answer fails in case 9!
variable to check
number=12345
or number=-23234
or number=23.167
or number=-345.234
check numeric or non-numeric
echo $number | grep -E '^-?[0-9]*\.?[0-9]*$' > /dev/null
decide on further actions based on the exit status of the above
if [ $? -eq 0 ]; then echo "Numeric"; else echo "Non-Numeric"; fi
[[ $1 =~ ^-?[0-9]+$ ]] && echo "number"
Don't forget -
to include negative numbers!
Just a follow up to @mary. But because I don't have enough rep, couldn't post this as a comment to that post. Anyways, here is what I used:
isnum() { awk -v a="$1" 'BEGIN {print (a == a + 0)}'; }
The function will return "1" if the argument is a number, otherwise will return "0". This works for integers as well as floats. Usage is something like:
n=-2.05e+07
res=`isnum "$n"`
if [ "$res" == "1" ]; then
echo "$n is a number"
else
echo "$n is not a number"
fi
Below is a Script written by me and used for a script integration with Nagios and it is working properly till now
#!/bin/bash
# Script to test variable is numeric or not
# Shirish Shukla
# Pass arg1 as number
a1=$1
a=$(echo $a1|awk '{if($1 > 0) print $1; else print $1"*-1"}')
b=$(echo "scale=2;$a/$a + 1" | bc -l 2>/dev/null)
if [[ $b > 1 ]]
then
echo "$1 is Numeric"
else
echo "$1 is Non Numeric"
fi
EG:
# sh isnumsks.sh "-22.22"
-22.22 is Numeric
# sh isnumsks.sh "22.22"
22.22 is Numeric
# sh isnumsks.sh "shirish22.22"
shirish22.22 is Non Numeric
I would try this:
printf "%g" "$var" &> /dev/null
if [[ $? == 0 ]] ; then
echo "$var is a number."
else
echo "$var is not a number."
fi
Note: this recognizes nan and inf as number.
I was looking at the answers and... realized that nobody thought about FLOAT numbers (with dot)!
Using grep is great too.
-E means extended regexp
-q means quiet (doesn't echo)
-qE is the combination of both.
To test directly in the command line:
$ echo "32" | grep -E ^\-?[0-9]?\.?[0-9]+$
# answer is: 32
$ echo "3a2" | grep -E ^\-?[0-9]?\.?[0-9]+$
# answer is empty (false)
$ echo ".5" | grep -E ^\-?[0-9]?\.?[0-9]+$
# answer .5
$ echo "3.2" | grep -E ^\-?[0-9]?\.?[0-9]+$
# answer is 3.2
Using in a bash script:
check=`echo "$1" | grep -E ^\-?[0-9]*\.?[0-9]+$`
if [ "$check" != '' ]; then
# it IS numeric
echo "Yeap!"
else
# it is NOT numeric.
echo "nooop"
fi
To match JUST integers, use this:
# change check line to:
check=`echo "$1" | grep -E ^\-?[0-9]+$`
As Charles Duffy's answer work, but only use bash regular expression, and I know this to be slow, I would like to show another way, using only bash parameter expansion:
For positive integers only:
is_num() { [ "$1" ] && [ -z "${1//[0-9]}" ] ;}
For integers:
is_num() {
local chk=${1#[+-]};
[ "$chk" ] && [ -z "${chk//[0-9]}" ]
}
Then for floating:
is_num() {
local chk=${1#[+-]};
chk=${chk/.}
[ "$chk" ] && [ -z "${chk//[0-9]}" ]
}
To match initial request:
set -- "foo bar"
is_num "$1" && VAR=$1 || echo "need a number"
need a number
set -- "+3.141592"
is_num "$1" && VAR=$1 || echo "need a number"
echo $VAR
+3.141592
There is a same check based on Charles Duffy's answer:
cdIs_num() {
local re='^[+-]?[0-9]+([.][0-9]+)?$';
[[ $1 =~ $re ]]
}
Some tests:
if is_num foo;then echo It\'s a number ;else echo Not a number;fi
Not a number
if cdIs_num foo;then echo It\'s a number ;else echo Not a number;fi
Not a number
if is_num 25;then echo It\'s a number ;else echo Not a number;fi
It's a number
if cdIs_num 25;then echo It\'s a number ;else echo Not a number;fi
It's a number
if is_num 3+4;then echo It\'s a number ;else echo Not a number;fi
Not a number
if cdIs_num 3+4;then echo It\'s a number ;else echo Not a number;fi
Not a number
if is_num 3.1415;then echo It\'s a number ;else echo Not a number;fi
It's a number
if cdIs_num 3.1415;then echo It\'s a number ;else echo Not a number;fi
It's a number
Ok, that's fine. Now how many time will take all this (On my raspberry pi):
time for i in {1..1000};do is_num +3.14159265;done
real 0m2.476s
user 0m1.235s
sys 0m0.000s
Then with regular expressions:
time for i in {1..1000};do cdIs_num +3.14159265;done
real 0m4.363s
user 0m2.168s
sys 0m0.000s
Can't comment yet so I'll add my own answer, which is an extension to glenn jackman's answer using bash pattern matching.
My original need was to identify numbers and distinguish integers and floats. The function definitions deducted to:
function isInteger() {
[[ ${1} == ?(-)+([0-9]) ]]
}
function isFloat() {
[[ ${1} == ?(-)@(+([0-9]).*([0-9])|*([0-9]).+([0-9]))?(E?(-|+)+([0-9])) ]]
}
I used unit testing (with shUnit2) to validate my patterns worked as intended:
oneTimeSetUp() {
int_values="0 123 -0 -123"
float_values="0.0 0. .0 -0.0 -0. -.0 \
123.456 123. .456 -123.456 -123. -.456
123.456E08 123.E08 .456E08 -123.456E08 -123.E08 -.456E08 \
123.456E+08 123.E+08 .456E+08 -123.456E+08 -123.E+08 -.456E+08 \
123.456E-08 123.E-08 .456E-08 -123.456E-08 -123.E-08 -.456E-08"
}
testIsIntegerIsFloat() {
local value
for value in ${int_values}
do
assertTrue "${value} should be tested as integer" "isInteger ${value}"
assertFalse "${value} should not be tested as float" "isFloat ${value}"
done
for value in ${float_values}
do
assertTrue "${value} should be tested as float" "isFloat ${value}"
assertFalse "${value} should not be tested as integer" "isInteger ${value}"
done
}
Notes: The isFloat pattern can be modified to be more tolerant about decimal point (@(.,)
) and the E symbol (@(Ee)
). My unit tests test only values that are either integer or float, but not any invalid input.
Old question, but I just wanted to tack on my solution. This one doesn't require any strange shell tricks, or rely on something that hasn't been around forever.
if [ -n "$(printf '%s\n' "$var" | sed 's/[0-9]//g')" ]; then
echo 'is not numeric'
else
echo 'is numeric'
fi
Basically it just removes all digits from the input, and if you're left with a non-zero-length string then it wasn't a number.
Following up on David W's answer from Oct '13, if using expr
this might be better
test_var=`expr $am_i_numeric \* 0` >/dev/null 2>&1
if [ "$test_var" = "" ]
then
......
If numeric, multiplied by 1 gives you the same value, (including negative numbers). Otherwise you get null
which you can test for
test -z "${i//[0-9]}" && echo digits || echo no no no
${i//[0-9]}
replaces any digit in the value of $i
with an empty string, see man -P 'less +/parameter\/' bash
. -z
checks if resulting string has zero length.
if you also want to exclude the case when $i
is empty, you could use one of these constructions:
test -n "$i" && test -z "${i//[0-9]}" && echo digits || echo not a number
[[ -n "$i" && -z "${i//[0-9]}" ]] && echo digits || echo not a number
The simplest way is to check whether it contains non-digit characters. You replace all digit characters with nothing and check for length. If there's length it's not a number.
if [[ ! -n ${input//[0-9]/} ]]; then
echo "Input Is A Number"
fi
Did the same thing here with a regular expression that test the entire part and decimals part, separated with a dot.
re="^[0-9]*[.]{0,1}[0-9]*$"
if [[ $1 =~ $re ]]
then
echo "is numeric"
else
echo "Naahh, not numeric"
fi
I'm surprised at the solutions directly parsing number formats in shell. shell is not well suited to this, being a DSL for controlling files and processes. There are ample number parsers a little lower down, for example:
isdecimal() {
# filter octal/hex/ord()
num=$(printf '%s' "$1" | sed "s/^0*\([1-9]\)/\1/; s/'/^/")
test "$num" && printf '%f' "$num" >/dev/null 2>&1
}
Change '%f' to whatever particular format you require.
This can be achieved by using grep
to see if the variable in question matches an extended regular expression.
1120
:yournumber=1120
if echo "$yournumber" | grep -qE '^[0-9]+$'; then
echo "Valid number."
else
echo "Error: not a number."
fi
Output: Valid number.
1120a
:yournumber=1120a
if echo "$yournumber" | grep -qE '^[0-9]+$'; then
echo "Valid number."
else
echo "Error: not a number."
fi
Output: Error: not a number.
grep
, the -E
switch allows us to use extended regular expression '^[0-9]+$'
. This regular expression means the variable should only []
contain the numbers 0-9
zero through nine from the ^
beginning to the $
end of the variable and should have at least +
one character.grep
, the -q
quiet switch turns off any output whether or not it finds anything.if
checks the exit status of grep
. Exit status 0
means success and anything greater means an error. The grep
command has an exit status of 0
if it finds a match and 1
when it doesn't;So putting it all together, in the if
test, we echo
the variable $yournumber
and |
pipe it to grep
which with the -q
switch silently matches the -E
extended regular expression '^[0-9]+$'
expression. The exit status of grep
will be 0
if grep
successfully found a match and 1
if it didn't. If succeeded to match, we echo "Valid number."
. If it failed to match, we echo "Error: not a number."
.
We can just change the regular expression from '^[0-9]+$'
to '^[0-9]*\.?[0-9]+$'
for floats or doubles.
1120.01
:yournumber=1120.01
if echo "$yournumber" | grep -qE '^[0-9]*\.?[0-9]+$'; then
echo "Valid number."
else
echo "Error: not a number."
fi
Output: Valid number.
11.20.01
:yournumber=11.20.01
if echo "$yournumber" | grep -qE '^[0-9]*\.?[0-9]+$'; then
echo "Valid number."
else
echo "Error: not a number."
fi
Output: Error: not a number.
To allow negative integers, just change the regular expression from '^[0-9]+$'
to '^\-?[0-9]+$'
.
To allow negative floats or doubles, just change the regular expression from '^[0-9]*\.?[0-9]+$'
to '^\-?[0-9]*\.?[0-9]+$'
.
You could use "let" too like this :
[ ~]$ var=1
[ ~]$ let $var && echo "It's a number" || echo "It's not a number"
It\'s a number
[ ~]$ var=01
[ ~]$ let $var && echo "It's a number" || echo "It's not a number"
It\'s a number
[ ~]$ var=toto
[ ~]$ let $var && echo "It's a number" || echo "It's not a number"
It\'s not a number
[ ~]$
But I prefer use the "=~" Bash 3+ operator like some answers in this thread.
As i had to tamper with this lately and like karttu's appoach with the unit test the most. I revised the code and added some other solutions too, try it out yourself to see the results:
#!/bin/bash
# N={0,1,2,3,...} by syntaxerror
function isNaturalNumber()
{
[[ ${1} =~ ^[0-9]+$ ]]
}
# Z={...,-2,-1,0,1,2,...} by karttu
function isInteger()
{
[[ ${1} == ?(-)+([0-9]) ]]
}
# Q={...,-½,-¼,0.0,¼,½,...} by karttu
function isFloat()
{
[[ ${1} == ?(-)@(+([0-9]).*([0-9])|*([0-9]).+([0-9]))?(E?(-|+)+([0-9])) ]]
}
# R={...,-1,-½,-¼,0.E+n,¼,½,1,...}
function isNumber()
{
isNaturalNumber $1 || isInteger $1 || isFloat $1
}
bools=("TRUE" "FALSE")
int_values="0 123 -0 -123"
float_values="0.0 0. .0 -0.0 -0. -.0 \
123.456 123. .456 -123.456 -123. -.456 \
123.456E08 123.E08 .456E08 -123.456E08 -123.E08 -.456E08 \
123.456E+08 123.E+08 .456E+08 -123.456E+08 -123.E+08 -.456E+08 \
123.456E-08 123.E-08 .456E-08 -123.456E-08 -123.E-08 -.456E-08"
false_values="blah meh mooh blah5 67mooh a123bc"
for value in ${int_values} ${float_values} ${false_values}
do
printf " %5s=%-30s" $(isNaturalNumber $value) ${bools[$?]} $(printf "isNaturalNumber(%s)" $value)
printf "%5s=%-24s" $(isInteger $value) ${bools[$?]} $(printf "isInteger(%s)" $value)
printf "%5s=%-24s" $(isFloat $value) ${bools[$?]} $(printf "isFloat(%s)" $value)
printf "%5s=%-24s\n" $(isNumber $value) ${bools[$?]} $(printf "isNumber(%s)" $value)
done
So isNumber() includes dashes, commas and exponential notation and therefore returns TRUE on integers & floats where on the other hand isFloat() returns FALSE on integer values and isInteger() likewise returns FALSE on floats. For your convenience all as one liners:
isNaturalNumber() { [[ ${1} =~ ^[0-9]+$ ]]; }
isInteger() { [[ ${1} == ?(-)+([0-9]) ]]; }
isFloat() { [[ ${1} == ?(-)@(+([0-9]).*([0-9])|*([0-9]).+([0-9]))?(E?(-|+)+([0-9])) ]]; }
isNumber() { isNaturalNumber $1 || isInteger $1 || isFloat $1; }
I use printf as other answers mentioned, if you supply the format string "%f" or "%i" printf will do the checking for you. Easier than reinventing the checks, the syntax is simple and short and printf is ubiquitous. So its a decent choice in my opinion - you can also use the following idea to check for a range of things, its not only useful for checking numbers.
declare -r CHECK_FLOAT="%f"
declare -r CHECK_INTEGER="%i"
## <arg 1> Number - Number to check
## <arg 2> String - Number type to check
## <arg 3> String - Error message
function check_number() {
local NUMBER="${1}"
local NUMBER_TYPE="${2}"
local ERROR_MESG="${3}"
local -i PASS=1
local -i FAIL=0
case "${NUMBER_TYPE}" in
"${CHECK_FLOAT}")
if ((! $(printf "${CHECK_FLOAT}" "${NUMBER}" &>/dev/random;echo $?))); then
echo "${PASS}"
else
echo "${ERROR_MESG}" 1>&2
echo "${FAIL}"
fi
;;
"${CHECK_INTEGER}")
if ((! $(printf "${CHECK_INTEGER}" "${NUMBER}" &>/dev/random;echo $?))); then
echo "${PASS}"
else
echo "${ERROR_MESG}" 1>&2
echo "${FAIL}"
fi
;;
*)
echo "Invalid number type format: ${NUMBER_TYPE} to check_number()." 1>&2
echo "${FAIL}"
;;
esac
}
>$ var=45
>$ (($(check_number $var "${CHECK_INTEGER}" "Error: Found $var - An integer is required."))) && { echo "$var+5" | bc; }
printf '%b' "-123\nABC" | tr '[:space:]' '_' | grep -q '^-\?[[:digit:]]\+$' && echo "Integer." || echo "NOT integer."
Remove the -\?
in grep matching pattern if you don't accept negative integer.
The accepted answer does not work here, I am on MacOS. The following code works:
if [ $(echo "$number" | grep -c '^[0-9]\+$') = 0 ]; then
echo "it is a number"
else
echo "not a number"
fi
To catch negative numbers:
if [[ $1 == ?(-)+([0-9.]) ]]
then
echo number
else
echo not a number
fi
The accepted answer didn't work for me in all cases BASH 4+ so :
# -- is var an integer? --
# trim leading/trailing whitespace, then check for digits return 0 or 1
# Globals: None
# Arguments: string
# Returns: boolean
# --
is_int() {
str="$(echo -e "${1}" | sed -e 's/^[[:space:]]*//' -e 's/[[:space:]]*$//')"
case ${str} in ''|*[!0-9]*) return 1 ;; esac
return 0
}
How to use it ?
Valid (will return 0 = true):
is_int "100" && echo "return 0" || echo "return 1"
Invalid (will return 1 = false) :
is_int "100abc" && echo "returned 0" || echo "returned 1"
is_int "" && echo "returned 0" || echo "returned 1"
is_int "100 100" && echo "returned 0" || echo "returned 1"
is_int " " && echo "returned 0" || echo "returned 1"
is_int $NOT_SET_VAR && echo "returned 0" || echo "returned 1"
is_int "3.14" && echo "returned 0" || echo "returned 1"
Output:
returned 0
returned 1
returned 1
returned 1
returned 1
returned 1
returned 1
note, in Bash, 1 = false, 0 = true. I am simply printing it out where instead something like this would be more likely :
if is_int ${total} ; then
# perform some action
fi
For my problem, I only needed to ensure that a user doesn't accidentally enter some text thus I tried to keep it simple and readable
isNumber() {
(( $1 )) 2>/dev/null
}
According to the man page this pretty much does what I want
If the value of the expression is non-zero, the return status is 0
To prevent nasty error messages for strings that "might be numbers" I ignore the error output
$ (( 2s ))
bash: ((: 2s: value too great for base (error token is "2s")
I like Alberto Zaccagni's answer.
if [ "$var" -eq "$var" ] 2>/dev/null; then
Important prerequisites: - no subshells spawned - no RE parsers invoked - most shell applications don't use real numbers
But if $var
is complex (e.g. an associative array access), and if the number will be a non-negative integer (most use-cases), then this is perhaps more efficient?
if [ "$var" -ge 0 ] 2> /dev/null; then ..
I use expr. It returns a non-zero if you try to add a zero to a non-numeric value:
if expr -- "$number" + 0 > /dev/null 2>&1
then
echo "$number is a number"
else
echo "$number isn't a number"
fi
It might be possible to use bc if you need non-integers, but I don't believe bc
has quite the same behavior. Adding zero to a non-number gets you zero and it returns a value of zero too. Maybe you can combine bc
and expr
. Use bc
to add zero to $number
. If the answer is 0
, then try expr
to verify that $number
isn't zero.
I use the following (for integers):
## ##### constants
##
## __TRUE - true (0)
## __FALSE - false (1)
##
typeset -r __TRUE=0
typeset -r __FALSE=1
## --------------------------------------
## isNumber
## check if a value is an integer
## usage: isNumber testValue
## returns: ${__TRUE} - testValue is a number else not
##
function isNumber {
typeset TESTVAR="$(echo "$1" | sed 's/[0-9]*//g' )"
[ "${TESTVAR}"x = ""x ] && return ${__TRUE} || return ${__FALSE}
}
isNumber $1
if [ $? -eq ${__TRUE} ] ; then
print "is a number"
fi
A clear answer has already been given by @charles Dufy and others. A pure bash solution would be using the following :
string="-12,345"
if [[ "$string" =~ ^-?[0-9]+[.,]?[0-9]*$ ]]
then
echo $string is a number
else
echo $string is not a number
fi
Although for real numbers it is not mandatory to have a number before the radix point.
To provide a more thorough support of floating numbers and scientific notation (many programs in C/Fortran or else will export float this way), a useful addition to this line would be the following :
string="1.2345E-67"
if [[ "$string" =~ ^-?[0-9]*[.,]?[0-9]*[eE]?-?[0-9]+$ ]]
then
echo $string is a number
else
echo $string is not a number
fi
Thus leading to a way to differentiate types of number, if you are looking for any specific type :
string="-12,345"
if [[ "$string" =~ ^-?[0-9]+$ ]]
then
echo $string is an integer
elif [[ "$string" =~ ^-?[0-9]*[.,]?[0-9]*$ ]]
then
echo $string is a float
elif [[ "$string" =~ ^-?[0-9]*[.,]?[0-9]*[eE]-?[0-9]+$ ]]
then
echo $string is a scientific number
else
echo $string is not a number
fi
Note: We could list the syntactical requirements for decimal and scientific notation, one being to allow comma as radix point, as well as ".". We would then assert that there must be only one such radix point. There can be two +/- signs in an [Ee] float. I have learned a few more rules from Aulu's work, and tested against bad strings such as '' '-' '-E-1' '0-0'. Here are my regex/substring/expr tools that seem to be holding up:
parse_num() {
local r=`expr "$1" : '.*\([.,]\)' 2>/dev/null | tr -d '\n'`
nat='^[+-]?[0-9]+[.,]?$' \
dot="${1%[.,]*}${r}${1##*[.,]}" \
float='^[\+\-]?([.,0-9]+[Ee]?[-+]?|)[0-9]+$'
[[ "$1" == $dot ]] && [[ "$1" =~ $float ]] || [[ "$1" =~ $nat ]]
} # usage: parse_num -123.456
I tried ultrasawblade's recipe as it seemed the most practical to me, and couldn't make it work. In the end i devised another way though, based as others in parameter substitution, this time with regex replacement:
[[ "${var//*([[:digit:]])}" ]]; && echo "$var is not numeric" || echo "$var is numeric"
It removes every :digit: class character in $var and checks if we are left with an empty string, meaning that the original was only numbers.
What i like about this one is its small footprint and flexibility. In this form it only works for non-delimited, base 10 integers, though surely you can use pattern matching to suit it to other needs.
Source: Stackoverflow.com