i am getting the following error while loading my index page in FF3.0. Sorry, i am unable to paste the script here as it is 2030 lines of code.
element.dispatchEvent is not a function
On expansion it gives me below things,
fire()()prototype.js?1 (line 3972)
_methodized()()prototype.js?1 (line 246)
fireContentLoadedEvent()prototype.js?1 (line 4006)
[Break on this error] element.dispatchEvent(event);
element.dispatchEvent(event); is in line 3972 of prototype.js. I am including prototype.js along with 10s of other js files in my index page.
Has anybody came across this kind of error? Please somebody explain me why this error is showing up.
This question is related to
javascript
firebug
element
dispatchevent
Change the following line
$(document).ready(function() {
To
jQuery.noConflict();
jQuery(document).ready(function($) {
are you using jquery and prototype on the same page by any chance?
If so, use jquery noConflict mode, otherwise you are overwriting prototypes $ function.
noConflict mode is activated by doing the following:
<script src="jquery.js"></script>
<script>jQuery.noConflict();</script>
Note: by doing this, the dollar sign variable no longer represents the jQuery object. To keep from rewriting all your jQuery code, you can use this little trick to create a dollar sign scope for jQuery:
jQuery(function ($) {
// The dollar sign will equal jQuery in this scope
});
// Out here, the dollar sign still equals Prototype
After all the Jquery script tag's add
<script>jQuery.noConflict();</script>
to avoid the conflict between Prototype and Jquery.
check for this by calling the library jquery after the noconflict.js or that this calling more than once jquery library after the noconflict.js
You have to add
<script>jQuery.noConflict();</script>
after
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
Source: Stackoverflow.com