What causes Notice Uninitialized string offset to appear

Question

I have a form that users fill out  and on the form there are multiple identical fields  like  project name    project date    catagory   etc  Based on how many forms a user is submitting  my goal is to    loop over the number of forms create individual SQL insert statements   However  PHP throws me a NOTICE that I don t seem to understand   Notice      Notice  Uninitialized string offset  1    dataPasser php on line 90   PHP   myQuery   array     if   varsCount    0      for   i 0   i  lt    varsCount   i             var    insert into projectData values        catagory  i               task  i              fullText  i              dueDate  i        null        empId  i             array push  myQuery   var                There are references to this issue I am having  but they are not exact and I am having trouble deducing where the actual problem stems from  I would greatly appreciate any help in understanding what is causing the array to not initialize properly

User · Answer

Check out the contents of your array with   echo   lt pre gt     print r   arr  TRUE       lt  pre gt

User · Answer

It means one of your arrays isn t actually an array   By the way  your if check is unnecessary  If  varsCount is 0 the for loop won t execute anyway

User · Answer

The error may occur when the number of times you iterate the array is greater than the actual size of the array  for example     one  909    for  i 0  i lt 10  i        echo      one  i     will show the error    first case u can take the mod of i   for example   function mod  i  length      m    i    size    if   m  gt   size    mod  m  size    return  m     for  i 0  i lt 10  i         k mod  i 3     echo      one  k       or might be it not an array  maybe it was a value and you tried to access it like an array    for example    k   2   k 0

User · Answer

Try to test and initialize your arrays before you use them    if   isset  catagory  i      catagory  i         if   isset  task  i      task  i         if   isset  fullText  i      fullText  i         if   isset  dueDate  i      dueDate  i         if   isset  empId  i      empId  i           If  catagory  i  doesn t exist  you create  Uninitialized  one     that s all      PHP try to read on your table in the address  i  but at this address  there s nothing  this address doesn t exist    PHP return you a notice  and it put nothing to you string  So you code is not very clean  it takes you some resources that down you server s performance  just a very little    Take care about your MySQL tables default values  if   isset  dueDate  i      dueDate  i     0000-00-00 00 00 00      or  if   isset  dueDate  i      dueDate  i     NULL

User · Answer

This error would occur if any of the following variables were actually strings or null instead of arrays  in which case accessing them with an array syntax  var  i  would be like trying to access a specific character in a string    catagory  task  fullText  dueDate  empId   In short  everything in your insert query   Perhaps the  catagory variable is misspelled

[php] What causes: "Notice: Uninitialized string offset" to appear?

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